Answer:
(a) g = 8.82158145
.
(b) 7699.990192m/s.
(c)5484.3301s = 1.5234 hours.(extremely fast).
Explanation:
(a) Strength of gravitational field 'g' by definition is
, here G is Gravitational Constant, and r is distance from center of earth, all the values will remain same except r which will be radius of earth + altitude at which ISS is in orbit.
r = 6721,000 meters, putting this value in above equation gives g = 8.82158145.
(b) We have to essentially calculate centripetal acceleration that equals new 'g'.
here g is known, r is known and v is unknown.
plugging in r and g in above and solving for unknown gives V = 7699.990192m/s.
(c) S = vT, here T is time period or time required to complete one full revolution.
S = earth's circumfrence , V is calculated in (B) T is unknown.
solving for unknown gives T = 5484.3301s = 1.5234hours.
Answer:
gravity
Explanation:
there eould be a different gravitational strenght on both of the planets causing it to weigh more, or less
Answer:
11m
Explanation:
Given:
Resistivity ρ = 5.6e-8 Ωm
Radius r = 0.045 mm 
= 4.5 x 10⁻⁵ m
Voltage V = 120V
Current I = 1.24A
From Ohm's law, 
R = 96.77 Ω
Resistivity = (Resistance × Area)/ length
ρ = (RA)/L
Therefore, the length of a wire is given by;
L = (RA)/ρ
Calculating the area A of the wire;
A = πr²
A = π × (4.5 x 10⁻⁵)²
A = 6.36 x 10⁻⁹ m²
Substituting area of the wire A = 6.36 x 10⁻⁹ m² into the equation of the length of wire
L = (96.77 × 6.36×10⁻⁹ ) / 5.6×10⁻⁸
L = 10.9977m
L = 11m (approximately)
Maximum because when moving in circular motion it move front to back
Answer:
An unmoving object will remain unmoving and a moving object in motion will continue to be in motion with the same velocity unless an external force acts upon it.
