Answer:
D or A ( I think)
Explanation:
Cause you know how people say the smaller the chips the more the chips its kind of the same with amplitude.
( hope it helps if I am wrong I am sorry)
Pretty sneaky, I must say !
Work = (force) x (distance)
That formula says nothing about the directions of the force OR
the distance. As long as they're both in the same direction, they
can both be horizontal (sliding a crate on the floor), vertical (lifting
something), or on any slant in between.
Roger's force and distance are both in the same direction ... the
direction of the incline ... so
Work = (60 newtons) x (10 meters) = 600 joules.
The structural damage which could be expected if a Category 3 hurricane which is predicted to hit an area is high percentage of framed homes could be destroyed, with total roof failure and wall collapse and is denoted as option C.
<h3>What is Hurricane?</h3>
This refers to the rapidly rotating storm which has a low-pressure center and is characterized by strong winds ad thunderstorms and of different types such as category 1 to 3.
Category 3 hurricane leads to loss of lives and properties which is depicted as framed homes being destroyed with total roof failure and wall collapse which is why option C was chosen.
Read more about Hurricane here brainly.com/question/2835662
#SPJ1
Answer:
Proof in explanation.
Explanation:
Consider a thin cylinder, whose thickness to diameter ration is less than 1/20, the hoop stress can be derived as follows:
Let,
L = length of cylinder
d = internal diameter of cylinder
t = thickness of wall of cylinder
P = internal pressure
σH = Hoop Stress
σL = Longitudinal Stress
Total force on half-cylinder owing to internal pressure = P x Projected Area = P x dL (Refer fig 9.1)
Total resisting force owing to hoop stress setup in walls = 2 σH L t
Therefore,
P d L = 2 σH L t
σH = Pd/2t _____________ eqn (1)
Now, for longitudinal stress:
Total force on end of cylinder owing to internal pressure = P x Projected Area = P x πd²/4
Area resisting this force = π d t (Refer fig 9.2)
Longitudinal Stress = Force/Area
σL = (Pπd²/4)/(πdt)
σL = Pd/4t ____________ eqn (2)
Dividing eqn (1) by eqn (2)
σH/σL = 2
<u>σH = 2 σL</u> (Hence, Proved)
Answer:
a) 75000Joules
b) 0Joules
Explanation:
Workdone = Force * Distance
Given
distance= 750m
Force = 300N
a) If the frictional force = 200N
The Total force = 300N - 200N = 100N
Work done = 100 * 750
Workdone = 75,000Joules
Hence the workdone if the force of friction is 200N is 75,000Joules
b) If the frictional force = 300N
The Total force = 300N - 300N = 0N
Work done = 0* 750
Workdone = 0Joules
Hence the workdone if the force of friction is 300N is 0Joules i.e no work will be done on the sled
