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ololo11 [35]
2 years ago
11

A 1.5 kg cart is attached to a spring with spring constant of 5 N/m. The cart & spring is pulled to stretch the spring by 3

meters.
What is the SPE?​
Physics
1 answer:
vaieri [72.5K]2 years ago
3 0

22.5 J

Explanation:

Given:

x = 3 m

k = 5\:\text{N/m}

The spring potential energy PE_s is

PE_s = \frac{1}{2}kx^2 = \frac{1}{2}(5\:\text{N/m})(3\:\text{m})^2

\:\:\:\:\:\:\:=22.5\:\text{J}

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