All categories

2 years ago

9. A body is a particular amount of matter. It can be a solid, liquid or gas. It can be

Physics

2 answers:

Phoenix [80]2 years ago

8 0

Answer:

time and space (A)

Explanation:

When something physically exists, it must exist in time and space. Matter/atoms are recognized as existing--which must be described by existence in time and space.

> Time and space exist as the <em>same</em> property (time cannot exist without space), and is called space-time

> Time is seen as relative {theory of special relativity} meaning that it <em>changes based on your perspective and the space it exists in. </em>

hope this helps!!

soldier1979 [14.2K]2 years ago

7 0

Answer:

B. Time and Space

Explanation:

Matter is a pshyical or corporeal susbtance in general, whether solid, liquid, or gaseous especially as distinguised from incorpeal substance, as spirit or mind, or form qualities, actions, and the

Within this time-and-space boundary, all matter exists. All matter is made up of atoms. Because these atoms take up space in the universe, solids, liquids, and gases are recognized as existing and may be found in all three dimensions.

Time is a figurative term. Space has three dimensions but time only has one.

You might be interested in

Three-point charges are arranged on a line. Charge q3 = +5.00nC and is at the origin. Charge q2 = -3.00 nC and is at x = 5.00 cm

Anon25 [30]

Answer:

Explanation:

Given

Charge $q_3=+5\ nC$ is placed at origin

Charge $q_2=-3\ nC$ is placed at $x=5\ cm$

Charge $q_1$ is Placed at $x=2.5\ cm$

charge $q_1$ must be positive so as to balance the force on charge $q_3$

Force on $q_3$ due to $q_1$ is

$F_{31}=\frac{kq_1q_3}{r^2}$

here $r=2.5\ cm$

$F_{31}=\frac{kq_1q_3}{(2.5)^2}$

Force on $q_3$ due to $q_2$ is

$F_{32}=\frac{kq_3q_2}{r^2}$

here $r=5\ cm$

$F_{32}=\frac{kq_3q_2}{(5)^2}$

$F_{31}=F_{32}$

$\frac{kq_1q_3}{(2.5)^2}=\frac{kq_3q_2}{(5)^2}$

$q_1=q_2(\frac{2.5}{5})^2$

$q_1=3\times (\frac{2.5}{5})^2$

$q_1=3\times \frac{1}{4}$

$q_1=0.75\ nC$

5 0

4 years ago

A skateboarder traveling at 7.0 meters per second rolls to a stop at the top of a ramp in 3.0 seconds. What is the skateboarder’

jasenka [17]

Answer:

let's help eachother if u want?.

Explanation:

Alexis and Kym arrange to meet at the running track to train for an athletics carnival. They cycle to the track, leaving their homes at the same time. It takes Alexis 8 minutes to travel 2800 m from her home to the track. Kym takes 18 minutes,

after travelling a distance of 6.12 km.

Alexis thought she was faster, but Kym was not convinced. Who do you think was faster? Give reasons for your answer.

3 0

3 years ago

Imagine a universe in which, like in ours, there are two kinds of charges (positive and negative), with the like charges repelli

GuDViN [60]

Answer:

the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

Explanation:

In this hypothetical system the electric force is of type

F = $k' \frac{q_1 q_2 }{r^2}$

in this case the force decays to zero much faster,

if we call Fo the force of Coulomb's law

F₀ = $k \frac{q_1 q_2 }{r^2}$

assuming the constant k is the same

the relationship between the two forces is

F / F₀ = 1 / r

F = F₀ / r

when analyzing this expression the force decays much faster to zero.

In an electric conductor, charges of the same sign may not feel any repulsive force from other charges that are at a medium distance, so there is a probability that some charges are distributed in the volume of the material, this does not happen with coulomb's law

Consequently, the static charge is not always distributed on the surface of the conductor, there are also charges in the volume but of lesser magnitude

5 0

3 years ago

In 10s a car accelerates 4m/s^2 to 60m/s. How fast was the car going before it accelerated?

slega [8]

v2 = v1 + at 60 = v1 + 4*10 v1 = 20 m/s

3 0

3 years ago

Dolphins rely on echolocation to be able to survive in the ocean. In a 20 °C ocean, a dolphin produces an ultrasonic sound with

Firdavs [7]

Answer:

wavelength = 0.01 m

distance = 162.8 m

Explanation:

Given that;

Speed of sound in water = 1,480 meters per second

Frequency of ultrasound = 125KHZ

From=

v=λf

v= speed of sound

λ= wavelength of sound

f= frequency of sound

λ= 1,480 ms-1/125 * 10^3 Hz

λ= 0.01 m

From

v = 2x/t

where;

v= velocity of sound in water

x= distance traveled

t = time taken

x = vt/2

x = 1,480 ms-1 * 0.220 s/2

x= 162.8 m

8 0

3 years ago