The magnetic field at the center of the arc is 4 × 10^(-4) T.
To find the answer, we need to know about the magnetic field due to a circular arc.
<h3>What's the mathematical expression of magnetic field at the center of a circular arc?</h3>
- According to Biot savert's law, magnetic field at the center of a circular arc is
- B=(μ₀ I/4π)× (arc/radius²)
- As arc is given as angle × radius, so
B=( μ₀I/4π)×(angle/radius)
<h3>What will be the magnetic field at the center of a circular arc, if the arc has current 26.9 A, radius 0.6 cm and angle 0.9 radian?</h3>
B=(μ₀ I/4π)× (0.9/0.006)
= (10^(-7)× 26.9)× (0.9/0.006)
= 4 × 10^(-4) T
Thus, we can conclude that the magnitude of magnetic field at the center of the circular arc is 4 × 10^(-4) T.
Learn more about the magnetic field of a circular arc here:
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Answer:
75 W
Explanation:
= temperature of the filament = 2100 K
= Emitting area of the filament = 1 cm² = 10⁻⁴ m²
= Emissivity = 0.68
= Stefan's constant = 5.67 x 10⁻⁸ Wm⁻²K⁻⁴
Using Stefan's law, Power output of the light bulb is given as

Answer:
The velocity of the recoil is 
Explanation:
Kinetic Energy

The mass of th gun is the both mass the shotgun and the arm shoulder combination

The velocity is negative because is in opposite direction of the bullet
Answer:
The box 1 moves faster.
Explanation:
lets
Mass =m kg
Initial velocity = u m/s
Initial velocity of box = 0 m/s
Let stake mass of block = m
When ball bounces back:
The final speed of the box = v
Final speed of ball = - u
Pi = Pf ( From linear momentum conservation)
m x u + m x 0 = m ( - u) + m v
mu + mu = m v
v= 2 u
When ball get stuck :
The final speed of ball and box = v
Pi = Pf ( From linear momentum conservation)
m x u + m x 0 = (m+m) v
v= u /2
So the box 1 moves faster.
Answer:
joule
Explanation:
is for work it is also repreasent by SI