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2 years ago

Energy is the capacity to do work or

Physics

1 answer:

nordsb [41]2 years ago

8 0

Answer:

Explanation:

Apple initially has Potential energy due to it's height and mass

as it falls this PE is converted to KE

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Is a mirrors surface transparent translucent or opaque how do you know.

Eva8 [605]

There are actually two different kinds of mirrors, and the answer is different
for each one.

-- Plain old everyday hand mirror, vanity mirror, bathroom mirror, makeup
mirror, etc.

Opaque, reflecting silver coating is on the back of the glass.
Light from your tongue or your teeth flows to the front surface of the glass,
through the glass, out of the back surface of the glass, bounces off of the silver
coating on the back, reverses its direction, enters the back surface of the glass,
comes back through the glass again, leaves the front of the glass, goes into your
eyes, and you can see your teeth or your tongue.

Both surfaces of the glass, as well as the glass in between the surfaces, are
transparent. The silver coating on the back is opaque. I know that, because
when I look at the back of a mirror, I can't see any light coming through it.
The coating on the back is also reflective ... a big part of the reason why
a mirror works.

-- Expensive mirrors used by astronomers and eye-doctors.
Known as "first surface" mirrors.

Opaque, reflecting silver coating is on the <em>front</em> of the glass.
Light from your tongue or your teeth flows toward the front surface of the glass,
but never actually gets there. It bounces off of the silver coating on the front of
the glass, reverses its direction, goes into your eyes, and you can see your teeth
or your tongue.

The glass is transparent, but that doesn't matter, because the light never reaches
the glass. It only goes as far as the opaque silver coating on the front, and is
reflected from there.

4 0

3 years ago

a 10kg model rocket is fired at a 60 degree angle from horizontal from the football field with a thrust of 200N. what is the acc

Nikolay [14]

Answer:

the acceleration of the rocket is: a=vemΔmΔt−g a = v e m Δ m Δ t − g .

Explanation:

I answered this before.

hope this helps! :)

5 0

3 years ago

A series circuit has four resistors. The current through one resistor is 810 mA. How much current is supplied by the source?0.81

Papessa [141]

Answer:

810 mA

Explanation:

In a series circuit, the current is the same through the system, so if the current through one resistor is 810 mA, the current supplied by the source will be 810 mA.

So, the answer is 810 mA

8 0

1 year ago

In a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallw

RSB [31]

Answer:

The coefficient of kinetic is

$u_{k}=0.59$

Explanation:

The forces in the axis 'x' and 'y' using law of Newton to find coefficient of kinetic friction

ΣF=m*a

ΣFy=W-N=0

ΣFy=Fn-Fu=m*a

$F_{u} =u_{k} *N\\F_{N}=25N\\N=W\\N=3.5kg*9.8\frac{m}{s^{2} }=34.3N$

$F_{N}-F_{u}=m*a\\F_{N}-u_{k}*N=m*a\\u_{k}*N=F_{N}-m*a\\u_{k}=\frac{F_{N}-m*a}{N}$

Now to find the coefficient can find the acceleration using equation of uniform motion accelerated

$v_{f} ^{2}=v_{o}^{2}+2*a(x_{f}-x_{o})\\x_{o}=0\\v_{o}=0\\v_{f} ^{2}=2*a*x_{f}\\a=\frac{v_{f} ^{2}}{2*a*x_{f}}\\ a=\frac{(1.53\frac{m}{s} )^{2}}{2*0.91m}\\a= 1.28 \frac{m}{s^{2} }$

So replacing the acceleration can fin the coefficient:

$u_{k}=\frac{F_{N}-m*a }{N}\\u_{k}=\frac{25N-(3.5kg*1.28\frac{m}{s^{2}} }{34.3N} \\u_{k}=0.59$

5 0

3 years ago

You are watching an archery tournament when you start wondering how fast an arrow is shot from the bow. Remembering your physics

lianna [129]

<h2>Answer:</h2>

<em><u>Velocity of throwing arrow = 43.13 m/s.</u></em>

<h2>Explanation:</h2>

In the question,

Let us say the height from which the arrow was shot = h

Distance traveled by the arrow in horizontal = 61 m

Angle made by the arrow with the ground = 2°

So,

From the <u>equations of the motion</u>,

$61 =u.t\\t=\frac{61}{u}$

Now,

Also,

Finally, the angle made is 2 degrees with the horizontal.

So,

Final horizontal velocity = v.cos20°

Final vertical velocity = v.sin20°

Now,

u = v.cos20° (No acceleration in horizontal)

Also,

$v=u+at\\vsin20=0+9.8(t)\\t=\frac{v.sin20}{9.8}$

So,

We can say that,

$\frac{v.sin20}{9.8}=\frac{61}{v.cos20}\\v^{2}.sin20.cos20=597.8\\v^{2}=1860.56\\v=43.13\,m/s$

<em><u>Therefore, the velocity with which the arrow was shot by the archer is 43.13 m/s.</u></em>

5 0

3 years ago