Answer:
maximum height = 31.63 m
Explanation:
Please notice that the units of velocity that you were giving are incorrect. They should be m/s. The ones given in the problem are in fact units of acceleration (not velocity). I am assuming that the initial velocity of the rock is 24.9 m/s to solve this problem.
Let's start by finding the time it takes the rock to reach that maximum height at which point, the velocity of the rock will be zero (just before changing its direction of movement and starting heading down.
We can use the fact that the initial velocity (
) of the rock is 24.9 m/s, the final velocity (
) at the maximum height is zero, and that the only acceleration it is getting is that of gravity (g) slowing down it motion:

Now we can use this time it takes the rock to reach the maximum height, in the kinematic expression for the distance covered:

The units of height will come directly in meters (m) after evaluating, since we use all the quantities in the SI system.
Answer:

Explanation:
Acceleration on a VT graph is the slope of the line at the given point. We can find the slope at 3 with Δy/Δx. This gives us (4-2)/(3-(-3)) which works out to be -3m/s^2
Answer:
The height is the same
Explanation:
Because they were at the same height but they fell at different velocities
Answer:
C
Explanation:
The name of the rock is usually derived from the sediment grain size.
Answer:
The deceleration is 
Explanation:
From the question we are told that
The height above firefighter safety net is 
The length by which the net is stretched is 
From the law of energy conservation

Where
is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )
and
is the potential energy of the before jumping which is mathematically represented at

and
is the kinetic energy of the person just before landing on the safety net which is mathematically represented at

and
is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )
So the above equation becomes

=> 
substituting values

Applying the equation o motion

Now the final velocity is zero because the person comes to rest
So


