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Mekhanik [1.2K]
3 years ago
5

The distance between two planets is 1600 km. How much time would the light

Physics
1 answer:
Snowcat [4.5K]3 years ago
6 0

Answer:

5.33*10^-3 seconds

Explanation:

c = d/t

c = speed of light constant (3.0*10^5 km/s)

d = distance (1600 km)

t = ?

3.0*10^5 = 1600/t

t = 1600/3.0*10^5

t = 5.33*10^-3 seconds

I hope this helped! :)

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Focusing on the present is a characteristic of the observant function.

<h3>What is an Observant personality trait?</h3>

This trait is characterized by people who pay much attention to themselves more than others.

This type of people focus on the present and ensure things are done without procrastination. This depicts the option D which makes it the most appropriate choice.

Read more about Observant trait here brainly.com/question/12283441

7 0
2 years ago
A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A
ANEK [815]

Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J

So, the gravitational potential energy of a squirrel is 53.312 J.

7 0
3 years ago
Onomic models
Naddik [55]

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3 0
3 years ago
Question 2 An ideal gas in a piston/cylinder device is compressed at constant temperature. The entropy of the ideal gas will:
Flura [38]

To solve the problem it is necessary to refer to the definition of entropy.

Entropy is defined aso

\Delta S = \frac{\Delta Q}{T}

Where,

\Delta Q = Heat exchange

T = Temperature

Since the heat exchange is conserved and it is an isothermal process where the temperature remains constant the change in entropy remains the same, ie \Delta S = 0 (Reamins same)

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8 0
4 years ago
A 10 g bullet is fired into, and embeds itself in, a 2 kg block attached to a spring with a force constant of 19.6 n/m and whose
dmitriy555 [2]

Answer:

x=0.478\ m is the compression in the spring

Explanation:

Given:

  • mass of the bullet, m=10\ g=0.01\ kg
  • mass of block, M=2\ kg
  • stiffness constant of the spring, k=19.6\ N.m^{-1}
  • initial velocity of the spring just before it hits the block, u=300\ m.s^{-1}

<u>Now since the bullet-mass gets embed into the block, we apply the conservation of momentum as:</u>

m.u=(M+m).v

0.01\times 300=(2+0.01)\times v

v=1.4925\ m.s^{-1}

Now this kinetic energy of the combined mass gets converted into potential energy of the spring.

\rm Kinetic\ energy=Spring\ potential\ energy

\frac{1}{2} (M+m).v^2=\frac{1}{2} k.x^2

\frac{1}{2} \times (2+0.01)\times 1.4925^2=\frac{1}{2} \times 19.6\times x^2

x=0.478\ m is the compression in the spring

4 0
3 years ago
Read 2 more answers
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