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Bess [88]
2 years ago
5

Pls answer asap!! I need help on this question!

Physics
2 answers:
evablogger [386]2 years ago
8 0

Hubble space telescope, Hubble deep field guide, moon, mercury, Saturn, sun, galaxy messier 101

andrey2020 [161]2 years ago
3 0

Answer:

1-Hubble Deep Field Galaxy

2-Galaxy Messier 101

3-Sun

4-Saturn

5-Mercury

6-Moon

7-Hubble Space Telescope

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Select the sentence that best describes why copper and some other metals are good conductors.
Crank
B) Copper atoms have a loosely held free electron in their outer shell that is able to move freely to other atoms.
5 0
3 years ago
Read 2 more answers
Which of Newton's laws of motion describes the motion of an object that has a net<br> force of ON?
algol [13]

Newton's first and second laws of motion both do, but I think the one you're looking for is: <em>The First Law of Motion</em>.  That description is a little more direct.

It says that if an object is not acted on by a net external force, then it continues in "constant, uniform motion".

3 0
2 years ago
An object is stopped at point ‘a’, and travels to point ‘c’ in 8s. What was its acceleration?
lutik1710 [3]

In SI units, its acceleration is  (the distance from A to C) / 32  m/s^2 .

7 0
3 years ago
3. A cart with mass of 30 kg is traveling with a velocity of 4.0 m/s. The
MaRussiya [10]

Answer:

39 m/s

Explanation:

8 0
2 years ago
Read 2 more answers
how fast will and in what direction will a 20kg object accelerate if one force pushes at a 30 degree angle and another pushes at
DiKsa [7]

Answer:

|a|=2.83\ m/s^2

\theta=75^o

Explanation:

<u>Net Force And Acceleration </u>

The Newton's second law relates the net force applied on an object of mass m and the acceleration it aquires by

\vec F_n=m\vec a

The net force is the vector sum of all forces. In this problem, we are not given the magnitude of each force, only their angles. For the sake of solving the problem and giving a good guide on how to proceed with similar problems, we'll assume both forces have equal magnitudes of F=40 N

The components of the first force are

\vec F_1=

\vec F_1=\ N

The components of the second force are

\vec F_2=

\vec F_2=\ N

The net force is

\vec F_n=

\vec F_n=\ N

The magnitude of the net force is

|F_n|=\sqrt{14.64^2+54.64^2}

|F_n|=\sqrt{3200}=56.57\ N

The acceleration has a magnitude of

\displaystyle |a|=\frac{|F_n|}{m}

\displaystyle |a|=\frac{56.57}{20}

|a|=2.83\ m/s^2

The direction of the acceleration is the same as the net force:

\displaystyle tan\theta=\frac{54.64}{14.64}

\theta=75^o

5 0
2 years ago
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