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2 years ago

What is the definition of zenith, altitude, horizon, circompolar stars, astrolabe, and doppler effect in astronomy?

Physics

1 answer:

Nikitich [7]2 years ago

3 0

zenith- the point in the sky or celestial sphere directly above an observer

altitude- the apparent height of a celestial object above the horizon, measured as an angle

horizon- a great circle of the celestial sphere, the plane of which passes through the center of the earth and is parallel to that of the apparent horizon of a place.

circompolar stars- (of a star or motion) above the horizon at all times in a given latitude.

astrolabe- One of the fundamental calculations in astrology is the position of the sun relative to the signs of the zodiac. The path of the sun as seen from Earth is called the ecliptic and the astrolabe calculates the position of the sun on this path.

doppler effect- The Doppler effect is the change in frequency or wavelength of a wave in relation to an observer who is moving relative to the wave source. It is named after the Austrian physicist Christian Doppler, who described the phenomenon in 1842.

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The radius of the earth is 6378 km. What is the diameter of the earth in meters?

Nesterboy [21]

To determine the diameter of the earth in metres first multiply the original value by 2.

6378 X 2 = 12 756 km.

Then convert km - m

1 km = 1000 m
12 756 km = ? m

12 756 • 1000 = 12 756 000 = 12 756 000 m or 1.2756 X 10 ^ 7 m

The final solution for the diameter is 1.2756 X 10 ^ 7 m.

7 0

3 years ago

What percentage of a lower trophic level's energy flows to the next higher trophic level? A. 1% b. 10% c. 50% d. 100% Please sel

ikadub [295]

Answer:

The answer is B; 10%

8 0

2 years ago

The earth has a radius of 6.38 × 106 m and turns on its axis once every 23.9 h.

Vladimir [108]

Answer:

a) V = 465.9 m/s

b) θ = 70.529°

Explanation:

Let's first calculate angular velocity of earth:

$\omega=\frac{2\pi}{23.9h}*1h/3600s$

Velocity of a person on Ecuador will be:

$V_E = \omega*R$

$V_E = 465.9 m/s$

For part b, since angular velocity is the same:

$\frac{\omega*R}{3}=\omega*(R*cos\theta )$

Solving for θ:

$\theta=acos(1/3)$

$\theta=70.529\°$

8 0

3 years ago

The main water line enters a house on the first floor. The line has a gauge pressure of 2.10 x 105 Pa. (a) A faucet on the secon

Eva8 [605]

To answer this question is necessary to apply the concepts related to Bernoulli's equation. The Bernoulli-related concept describes the behavior of a liquid moving along a streamline. Pressure can be defined as the proportional ratio between height, density and gravity:

$P = h\rho g$

Where,

h = Height

$\rho$ = Density

g = Gravity

Our values are

$\rho = 1000kg/m^3 \rightarow$ density of water at normal conditions

h = 7.3m

$g = 9.8m/s^2$

PART A) Replacing these values to find the total pressure difference we have to

$P_1 = h_1 \rho g$

$P_1 = (7.3)(1000)(9.8)$

$P_1 = 71540Pa$

In this way the pressure change would be subject to

$\Delta = P_2-P_1$

$\Delta = 2.1*10^5Pa- 0.7154*10^5Pa$

$\Delta = 138460Pa$

$\Delta = 0.135Mpa$

PART B) Considering the pressure gauge of the group as the ideal so that at a height H the water cannot flow even if it is open we have to,

$P_2 = H\rho g$

$2.1*10^5 = H (1000)(9.8)$

$H = 21.42m$

Therefore the high which could a faucet be before no water would flow from it is 21.42m

5 0

3 years ago

A vehicle has an oil leak that is causing the entire oil pan to be wet, but inspection reveals no exact source after cleaning of

attashe74 [19]

Answer:

Technician A is correct

Explanation:

The best approach to solve the problem is that of technician A. using a fluorescent die is the easiest and most efficient way to trace leaks with unknown sources. The fluorescent die will simply illuminate the path to the leaking spot in the engine of the car, without any need for much speculations. This makes this method a sure approach.

However, Technician B's approach still has a lot of assumptions factored into the methodology, and would not work properly. It will still require the painstaking attempts trying to make guesses where the oil leak is coming from, which will lead to wastage of time and energy.

This makes Technician A have the right approach to solving the problem

7 0

3 years ago