Answer:
3.74L
Explanation:
PV=nRT
V=nRT/P
= 0.25mol*0.0821LatmK^-1*273k/1.50atm
=3.74L
We have been given the OH⁻ ion concentration, we can calculate the pOH concentration.
pOH = -log [OH⁻]
pOH = - log (5.5 x 10⁻⁵ M)
pOH = 4.26
we can then calculate the pH value
pH + pOH = 14
pH = 14 - 4.26
pH = 9.74
since pH > 7 the solution is basic.
by knowing the pH value, we can calculate the H₃O⁺ concentration
pH = - log[H₃O⁺]
[H₃O⁺] = antilog (-pH) = antilog (-9.74)
[H₃O⁺] = 1.82 x 10⁻¹⁰ M
Answer:
HgBr₂.
Explanation:
- To determine the empirical formula of the mercury bromide that is produced, we should calculate the no. of moles of Hg (1.750 g) and Br (1.394 g) used to prepare the mercury bromide.
no. of moles of Hg = mass/atomic mass = (1.75 g)/(200.59 g/mol) = 0.00872 mol.
no. of moles of Br = mass/atomic mass = (1.394 g)/(79.904 g/mol) = 0.01744 mol.
- We divide by the lowest no. of moles (0.00872) to get the mole ratio:
The mole ratio of (Br: Hg) is: (2: 1).
<em>So, the empirical formula is: HgBr₂.</em>
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The multiple-choice answer is (A)
Element. a pure substance that cannot be separated or broken down into simpler substances by physical or chemical means. pure substance. a substance in which here is only one type of particle; includes elements and compounds.
