Use the problem below to answer the question:

During a skin burn from an oven, approximate the skin and tissue layer to be infinitely thick compared to the damaged layer. The

Vlad [161]

Answer:

The depth of the damage is given as $x = 1.357*10^{-3}m$

Explanation:

From Fick's second law

$\frac{C_{x}-C_{0}}{C_{s}-C_{0}} = 1 -erf [\frac{x}{2\sqrt{Dt} } ] ...(1)$

Where

$C_x$ is the temperature when the skin is damage

$C_0$ is the initial temperature of the skin

$Cs$ is the temperature of the oven

erf is a mathematical function known as error function

D is the thermal diffusivity

x is the depth of the damage

From the question we are given that

$C_x$ = 62°C

$C_0$ = 33°C

D = $2.5 * 10^{-7} m^2/s.$

Substituting values into equation one

$\frac{62-33}{200-33} = 1 -erf [\frac{x}{2\sqrt{2.5*10^{-7}} *2} ]$

$erf[\frac{x}{1.414*10^{-3}} ] = 0.826\\$

Let assume that $z =\frac{x}{1.414*10^{-3}} ... (2)$

Hence

$erf(z) = 0.826$

Looking at the table of error function shown on the first uploaded image

We can use interpolation to obtain the value of z in this manner

$\frac{z-0.95}{0.8260-0.8209} = 1$

z = 0.96

Substituting the value of z into equation 2

$0.96 = \frac{x}{1.414*10^{-3}}$

$x = 1.357*10^{-3}m$

5 0

3 years ago

Calculate the root mean square velocity of F2,Cl2, and Br2 at 304 K .

Artist 52 [7]

<span>The root mean square velocity of gas molecules as a function of temperature is (M is molecular weight):
v²rms = 3RT/M,
and kinetic energy is given by:
KE = ½Mv ²
We can make the substitution:
KE = ½M3RT/M, or
KE = (3/2)RT.
Notice the molecular weight variable is gone; that means the answer will be the same for F2, Cl2, and Br2:
KE = (3/2) (8.314 J/K*mole) (290 K) = 3617 J/mole.</span>

5 0

3 years ago

What is the number of significant figures in 12.0160 mL of water?

likoan [24]

Answer:

To calculate the number of significant figures in a number with decimal,

start at the first non-zero digit in the number and count the total number of digits till the end

hence, in this number:

we will have 6 significant figures

4 0

4 years ago

Calculate the concentration (M) of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to

Luda [366]

The concentration of sodium ions in a solution made by diluting 10.0 mL of a 0.774 M solution of sodium sulfide to a volume of 100 mL would be 0.1548 M.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must be the same. This is expressed as the following equation:

$m_1v_1 = m_2v_2$

Where $m_1$ is the molarity before dilution, $v_1$ is the volume before dilution, $m_2$ is the molarity after dilution, and $v_2$ is the volume after dilution.