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marta [7]
2 years ago
14

an object is placed 20cm from a converging lens. If the real image is formed 80cm from the object, what is the focal length of t

he lens?​
Physics
1 answer:
masya89 [10]2 years ago
8 0

Explanation:

Here,

object distance(u)=20cm

image distance(v)=80cm-20cm=60cm

focal length(f)=?

we know ,

(1/f)=(1/v)+(1/u)

1/f = 1/60 + 1/20

1/f = (1+3)/60

60 =4f

f=15cm

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Is bath oil a homologenous mixture?
DaniilM [7]
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<span>Examples: </span>
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5 0
3 years ago
Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bu
MArishka [77]

Complete Question:

Suppose that an asteroid traveling straight toward the center of the earth were to collide with our planet at the equator and bury itself just below the surface. What would have to be the mass of this asteroid, in terms of the earth’s mass M, for the day to become 25.0% longer than it presently is as a result of the collision? Assume that the asteroid is very small compared to the earth and that the earth is uniform throughout.

Answer:

m = 0.001 M

For the whole process check the following page: https://www.slader.com/discussion/question/suppose-that-an-asteroid-traveling-straight-toward-the-center-of-the-earth-were-to-collide-with-our/

6 0
3 years ago
I will be so thankful if u answer correctly!!​
polet [3.4K]

(C) 200 N

Explanation:

The acceleration due to gravity on earth g_{E} is given by

g_{E} = G\dfrac{M_{E}}{R_{E}^{2}}

where G = universal gravitational constant

\:\:\:\:\:\:\:\:\:\:\:\:M_{R} = mass of the earth

\:\:\:\:\:\:\:\:\:\:\:\:R_{E} = radius of the earth

Planet Krypton has twice the mass of earth and 3 times the radius so its acceleration due to gravity g_{K} is

g_{K} = G\dfrac{M_{K}}{R_{K}^{2}}

\:\:\:\:\:\: = G\dfrac{(2M_{E})}{(3R_{E})^{2}}

\:\:\:\:\;\:= (\dfrac{2}{9})G\dfrac{M_{E}}{R_{E}^{2}}

or

g_{K} = (\dfrac{2}{9})\:g_{E}

If we multiply both sides by Superman's mass, we get his weights on both planets:

mg_{K} = (\dfrac{2}{9})\:(mg_{E})

W_{K} = (\dfrac{2}{9})\:W_{E} = (\dfrac{2}{9})(900\:N)= 200\:N

3 0
3 years ago
How could you increase the gravitational potential energy between yourself and Earth?
Tamiku [17]
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The only value that be controlled here is the height h.  The mass is constant, and acceleration due to gravity at that place is constant.

But h can be varied.

Hence to increase the gravitational potential energy between yourself and Earth is to increase the height h.

This can be done by climbing up a table, or climbing up a building through the stairs, or by using a lift.
5 0
3 years ago
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