Ask question

Ask question

All categories

2 years ago

14

an object is placed 20cm from a converging lens. If the real image is formed 80cm from the object, what is the focal length of t

he lens?

1 answer:

masya89 [10]2 years ago

8 0

Explanation:

Here,

object distance(u)=20cm

image distance(v)=80cm-20cm=60cm

focal length(f)=?

we know ,

(1/f)=(1/v)+(1/u)

1/f = 1/60 + 1/20

1/f = (1+3)/60

60 =4f

f=15cm

You might be interested in

How is the control group and experimental group different

zzz [600]

The control group is the independent variable and the experimental group is the dependent due to change during the experiment. The experimental group will usually rely on another variable in the experiment for change.

4 0

4 years ago

I need to know the answer

Phoenix [80]

i think number 1 is D number 2 is B

4 0

3 years ago

PLEASE HELP ME! IM TIMED

viktelen [127]

The last answer I think

3 0

3 years ago

Human centrifuges are used to train military pilots and astronauts in preparation for high-g maneuvers. A trained, fit person we

jeka57 [31]

(a) $4.14 rad/s^2$

The relationship beween centripetal acceleration and angular speed is

$a=\omega^2 r$

where

$\omega$ is the angular speed

r is the radius of the circular path

Here we gave

$a = 9g = 88.2 m/s^2$ is the centripetal acceleration

r = 5.15 m is the radius

Solving for $\omega$ , we find:

$\omega = \sqrt{\frac{a}{r}}=\sqrt{\frac{88.2 m/s^2}{5.15 m}}=4.14 rad/s^2$

(b) 21.3 m/s

The relationship between the linear speed and the angular speed is

$v=\omega r$

where

v is the linear speed

$\omega$ is the angular speed

r is the radius of the circular path

In this problem we have

$\omega=4.14 rad/s$

r = 5.15 m

Solving the equation for v, we find

$v=(4.14 rad/s)(5.15 m)=21.3 m/s$

7 0

3 years ago

Read 2 more answers

PLZ HELP NEED ANSWER!!!!!!!!!!!!!!!!!!!!

Naddika [18.5K]

Answer:

The answer is A. Synthetic

Explanation:

Synthetic materials are made by mankind, or in other words, human-made.

4 0

3 years ago