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2 years ago

How could you increase the gravitational potential energy between yourself and Earth?

1 answer:

5 0

Gravitational Potential Energy, GPE = mgh

Where m is your mass in kg, g is acceleration due to gravity = 9.8 m/s², and h is the height in m.

The only value that be controlled here is the height h. The mass is constant, and acceleration due to gravity at that place is constant.

But h can be varied.

Hence to increase the gravitational potential energy between yourself and Earth is to increase the height h.

This can be done by climbing up a table, or climbing up a building through the stairs, or by using a lift.

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A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x =

frutty [35]

Answer:

θ = (7π / 3) rad

Explanation:

given,

displacement of simple harmonic motion along x-axis

equation is given as

x = 5 sin (π t + π/3 )

general equation of simple harmonic motion

x = A sin θ

θ is the phase angle

θ = π t + π/3

at t = 2 s

$\theta =\pi \times 2 +\dfrac{\pi}{3}$

$\theta =\dfrac{7\pi}{3}\ rad$

Phase of the motion at t =2 s is θ = (7π / 3) rad

7 0

3 years ago

A ball is dropped from an upper floor, some unknown distance above your apartment. As you look out of your window, which is 1.50

laila [671]

Answer:

The ball is dropped at a height of 9.71 m above the top of the window.

Explanation:

<u>Given:</u>

Height of the window=1.5 m
Time taken by ball to cover the window height=0.15

Now using equation of motion in one dimension we have

$s=ut+\dfrac{at^2}{2}$

Let u be the velocity of the ball when it reaches the top of the window

then

$1.5=0.15u+\dfrac{9.8\times0.15^2}{2}\\u=3.96\ \rm m/s\\$

Now u is the final velocity of the ball with respect to the top of the building

so let t be the time taken for it to reach the top of the window with this velocity

$3.96=gt\\t=0.4\ \rm s\\$

Let h be the height above the top of the window

$h=\dfrac{gt^2}{2}\\\\h=\dfrac{9.8\times 0.4^2}{2}\\h=9.71\ \rm m$

3 0

3 years ago

.A box falls to the ground from a delivery truck traveling at 30 m/s. After hitting the road, it slides 45 m to

Romashka-Z-Leto [24]

Answer:

t = 3 seconds

Explanation:

Given that,

Initial speed, u = 30 m/s

Final speed, v = 0

It slides 45 m to rest.it take the box to come to rest

We need to find how long it take the box to come to rest.

Let a be the acceleration and t is time.

$v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(30)^2-u^2}{2(45)}\\\\=10\ m/s^2$

Now finding time.

$t=\dfrac{v-u}{a}\\\\t=\dfrac{30-0}{10}\\\\t=3\ s$

So, the required time is 3 seconds.

8 0

3 years ago

An 80.0 kg hiker walks a distance of 400.0 m along a road that slopes 5.0 degrees upward, and then stops. What is the hiker's fi

lana66690 [7]

The height difference is found by
$\delta H=400sin(5 \°)=34.86m$
Then the change in potential energy is
$E=mgh=(80.0kg)(9.8 \frac{kgm}{s^2})(34.86)= 27332J$

4 0

3 years ago

A 3. 5-a current is maintained in a simple circuit with a total resistance of 1500 ω. What net charge passes through any point i

melamori03 [73]

Electric Current:

Electric current is the flow of charge through a given circuit per unit time. Electric current is one of the components needed to calculate the electric power that a device needs to operate and do work. Electric current is measured in amperes (A), which is equal to:

1A = 1 C/ s

Recall that the coulomb (C) is the unit for charge while the second (s) is the unit for time

Given: I = 3.5

A is the current

Δt =30 s is the time interval

A =ΔQ/ΔT

Net charge = 100C

Electricity is produced when an electric current runs through a circuit.

How does electric current work?

A current of electricity is a steady flow of electrons. When electrons move from one place to another, round a circuit, they carry electrical energy from place to place like marching ants carrying leaves. Instead of carrying leaves, electrons carry a tiny amount of electric charge.

Learn more about Electric current :

brainly.com/question/27003377

#SPJ4

7 0

1 year ago