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stira [4]
2 years ago
11

Given that [OH-] = 5.46x10^-9M

Chemistry
1 answer:
grigory [225]2 years ago
8 0
  • pOH=-log[OH-]
  • pOH=-log[5.46×10^{-9}]
  • pOH=-log5.46-log10^-9
  • pOH=-0.74+9
  • pOH=8.26

pH:-

  • 14-pOH
  • 14-8.26
  • 5.74

It's acidic as pH<7

Now

  • -log[H+]=5.74
  • log[H+]=-5.74
  • H+=10^{-5.74}
  • H+=1.81×10^-6M
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