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Tomtit [17]
4 years ago
14

Which of the following statements is true? Protons have a mass that contributes significantly to the mass of the atomic nucleus.

Neutrons do not have a mass that contributes significantly to the mass of the atomic nucleus. Neutrons have a mass that contributes significantly to the mass of the atomic nucleus. Electrons have a mass that contributes significantly to the mass of the atomic nucleus.
Chemistry
1 answer:
Lunna [17]4 years ago
3 0
The following statements from the paragraph are true. Protons have a mass that contributes significantly to the mass of the atomic nucleus. Neutrons have a mass that contributes significantly to the mass of the atomic nucleus. Electrons have a very low mass and are not found in the nucleus but instead are found in surrounding orbits.
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.Inherited traits are passed from parent to offspring by information coded in
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the DNA or Deoxyribonucleic Acid

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Which of the following is an example of a genetically modified crop?
lord [1]

Answer:

Explanation:

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Laughing gas, N2O, also known as nitrous oxide contains 28.01 g of nitrogen in every 44.01 g of nitrous oxide. What mass of nitr
Sav [38]

Answer : The mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.

Explanation :

As we are given that, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide. Now we have to determine the mass of nitrous oxide formed from 85.20 g of nitrogen.

As, 28.01 g of nitrogen is present in 44.01 g of nitrous oxide

So, 85.20 g of nitrogen is present in \frac{85.20}{28.01}\times 44.01=133.9g of nitrous oxide

Thus, the mass of nitrous oxide formed from 85.20 g of nitrogen is, 133.9 grams.

4 0
3 years ago
A common fuel additive that is composed of C, H, and O enhanced the performance of gasoline began being phased out in 1999 becau
spayn [35]

Answer:

C₅ H₁₂ O

Explanation:

44 g of CO₂ contains 12 g of C

30.2 g of CO₂ will contain 12 x 30.2 / 44 = 8.236 g of C .

18 g of H₂O contains 2 g of hydrogen

14.8 g of H₂0 will contain 1.644 g of  H .

total compound = 12.1 out of which 8.236 g is C and 1.644 g is H , rest will be O

gram of O = 2.22

moles of C, O, H in the given compound =  8.236 / 12 , 2.22 / 16 , 1.644 / 1

= .6863 , .13875 , 1.644

ratio of their moles = 4.946 : 1 : 11.84

rounding off to digits

ratio = 5 : 1 : 12

empirical formula = C₅ H₁₂ O

6 0
4 years ago
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