Answer:
Step-by-step explanation:
<u>Given function is:</u>
Put x = 4
So,
![f(4) = 4^4\\\\f(4) = 256\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=f%284%29%20%3D%204%5E4%5C%5C%5C%5Cf%284%29%20%3D%20256%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Three diagonals can be drawn in a hexagon mmyyy dude.
Answer:
C = 288 kg
Step-by-step explanation:
Given:
C = 72m^2/4
where,
C = approximate number of calories
m = animal mass in kilograms.
Find C when m = 16
C = 72m^2/4
= 72 * (16)^2/4
= 72 * (16)^1/2
= 72 * √16
= 72 * 4
= 288
C = 288 kg
This is the concept of application of quadratic equations; To get the number of dimes and quarters we proceed as follows;
suppose there are x dimes and y quarters;
x+y=95.......i
but we know;
$0.1=1 dimes
$0.25=1 quarters
thus
0.1x+0.25y=23.45.....ii
solving equation i and ii by substitution we shall have:
from i;
x=95-y
thus substituting the value of x in equation ii we get
0.1(95-y)+0.25y=23.45
9.5-0.1y+0.25y=23.45
collecting like terms we get:
0.15y=13.95
dividing both sides by 0.15 we get;
y=13.95/0.15=93
x=95-93=2
therefore we conclude that there were 2 dimes and 93 quarters
