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3 years ago

An entertainer pulls a table cloth off a table leaving behind the plates and sliverware undisturbed is an example of

Physics

1 answer:

umka2103 [35]3 years ago

5 0

Answer:

D. Newton's first law

Explanation:

Newton's first law of inertia says that an object will remain how it is, unless affected by an outside force. In this case, the plates want to remain stationary(not moving). Therefore, if you pull the table cloth fast enough, the force of friction produced will be small enough so that the Inertia of the plates will overcome the force of friction.

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A 15.0 cm diameter circular loop of wire is placed with the plane of the loop parallel to the uniform magnetic field between the

velikii [3]

Answer:0.0144 tesla

Explanation:

Magnetic field strength is the same as Magnetomotive force

B= I/2πr

B=magnetic field strength

I=current

r=radius=0.15/2=0.75m

Area=πr2= 1.77m2

torqueT= NIABsin theta

B= T/NIABsin theta

B=0.135/1 * 5.3 * 1.77 *sin90

B=0.0144 tesla

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3 years ago

A Juggler is juggling a uniform rod one end of which is coated in tar and burning. He is holding the rod by the opposite end and

lyudmila [28]

The vertical speed of the rod varies inversely as the rotational speed for a given number of complete rotations

The equation that gives the vertical velocity, v₀ is $\, \underline{v_0= \dfrac{ g \cdot \pi \cdot n}{ \omega_0 }}$

Reason:

From a similar question, the given parameters appear to be correctly given as follows;

The vertical speed of the rod = v₀

Angular velocity of the = ω₀

Required;

The value of, v₀, so that the rod has made exactly, n, number of turns when it returns to his hand

Where;

n = An integer

Solution;

The time the rod spends in the air is given as follows;

$Height, \ h = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2$

Where;

g = Acceleration due to gravity

t = Time of motion

When the rod returns to his hand, we have, h = 0, therefore;

$0 = u \cdot t - \dfrac{1}{2} \cdot g \cdot t^2$

$u \cdot t = \dfrac{1}{2} \cdot g \cdot t^2$

$t^2 = \dfrac{u \cdot t }{\dfrac{1}{2} \cdot g } = \dfrac{2 \cdot u \cdot t }{g }$

$Time, \ t = \dfrac{2 \cdot u }{g }$

We have;

$Angular \ velocity, \ \omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{t} \ (required)$

$\omega_0 = \dfrac{ 2 \cdot \pi \cdot n}{ \dfrac{2 \cdot v_0 }{g }} = \dfrac{ g \cdot \pi \cdot n}{ v_0 }$

Therefore;

$The \ vertical \ velocity, \, \underline{v_0= \dfrac{ g \cdot \pi \cdot n}{ \omega_0 }}$

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brainly.com/question/14140053

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3 years ago

The radius of the earth's very nearly circular orbit around the sun is 1.5×1011m. find the magnitude of the earth's velocity. as

Luden [163]

Step 1 of 3 Calculate the magnitude of the earthâ€™s velocity. The radius of earth orbit around the sun is . Time taken to complete one revolution is . Convert time from days into seconds. The expression for magnitude of earth velocity is, Substitute for , for . Further solved, Explanation | Common mistakes | Hint for next step Time taken to complete one resolution is 365 days. Convert time from days into seconds. Radius of earth orbit around the sun is given. Velocity is circumference of orbit upon time taken in one resolution. Calculate the magnitude of earth velocity. Change unit of velocity to Step 2 of 3

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3 years ago

Astronomers study radio waves to learn about

il63 [147K]

Answer:

Radio astronomy began in 1933 when an engineer named Karl Jansky accidentally discovered that radio waves come not just from inventions we create but also from natural stuff in space.

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4 years ago

PLEASE HELP QUICKLY 50 POINTS Fracturing can emit ______waves through the ground.

drek231 [11]

Answer:

Fracturing can emit seismic waves through the ground.

Explanation:

I believe the answer is seismic, I've studied this before.

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3 years ago