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OverLord2011 [107]
3 years ago
14

¿Cuál es el rango de frecuencias comprendido entre las longitudes de onda de 220 nm, 350 nm,

Physics
1 answer:
olchik [2.2K]3 years ago
3 0

Answer:

f1 = 1.36*10^15 Hz

f2 = 8.57*10^14 Hz

f3 = 3.75*10^14 Hz

f4 = 8.57*10^13 Hz

Explanation:

To know which are the frequency ranges of the wavelengths you use the following formula:

c=\lambda f\\\\f=\frac{c}{\lambda}

c: speed of light = 3*10^8m/s

λ: wavelength = 220nm, 350nm, 800nm, 3500nm

f: frequency of the wave

You calculate f for each wavelength, furthermore, you add the kind of electromagnetic wave:

λ1 = 220nm = 220*10^-9 m

f=\frac{3*10^8m/s}{220*10^{-9}m}=1.36*10^{15}Hz   ULTRAVIOLET

λ2 = 350nm = 350*10^-9 m

f=\frac{3*10^8m/s}{350*10^{-9}m}=8.57*10^{14}Hz   VISIBLE LIGHT

λ3 = 800nm = 350*10^-9 m

f=\frac{3*10^8m/s}{800*10^{-9}m}=3.75*10^{14}Hz   INFRARED    

λ4 = 3500nm = 350*10^-9 m

f=\frac{3*10^8m/s}{3500*10^{-9}m}=8.57*10^{13}Hz   MICROWAVE - INFRARED

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an object has a mass of 50kg, a final height of 20m and an initial height of 8m. what is the amount of work done
Andrei [34K]

amount of work done is 5880 J

Given:

mass of object = 50kg

Final height = 20m

initial height = 8m

To Find:

amount of work done

Solution:

work is done when a force acts upon an object to cause a displacement. You can calculate the energy transferred, or work done, by multiplying the force by the distance moved in the direction of the force.

The work done by gravity is given by the formula,

W = mgh

W = 50 x 9.8 x ( 20-8)

= 5880 J

So the work done is 5880 J

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brainly.com/question/25239010

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7 0
1 year ago
What is the net force on this object f air = 400n (up) fgrav=600n (down)
n200080 [17]
Fnet=F1+F2 or Fnet=F1-F2
So 400n up - 600n down
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5 0
3 years ago
Read 2 more answers
A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.
MakcuM [25]

Answer:

b. 9.5°C

Explanation:

m_i = Mass of ice = 50 g

T_i = Initial temperature of water and Aluminum = 30°C

L_f = Latent heat of fusion = 3.33\times 10^5\ J/kg^{\circ}C

m_w = Mass of water = 200 g

c_w = Specific heat of water = 4186 J/kg⋅°C

m_{Al} = Mass of Aluminum = 80 g

c_{Al} = Specific heat of Aluminum = 900 J/kg⋅°C

The equation of the system's heat exchange is given by

m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C

The final equilibrium temperature is 9.50022°C

4 0
3 years ago
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podryga [215]
Your answer is "<span>surface of a sphere"

Hope this helps.</span>
3 0
3 years ago
in the derivation of the time period of a pendulum in electric field when considering the fbd of bob to find the g effective why
Neko [114]

Answer:

we learned that an object that is vibrating is acted upon by a restoring force. The restoring force causes the vibrating object to slow down as it moves away from the equilibrium position and to speed up as it approaches the equilibrium position. It is this restoring force that is responsible for the vibration. So what forces act upon a pendulum bob? And what is the restoring force for a pendulum? There are two dominant forces acting upon a pendulum bob at all times during the course of its motion. There is the force of gravity that acts downward upon the bob. It results from the Earth's mass attracting the mass of the bob. And there is a tension force acting upward and towards the pivot point of the pendulum. The tension force results from the string pulling upon the bob of the pendulum. In our discussion, we will ignore the influence of air resistance - a third force that always opposes the motion of the bob as it swings to and fro. The air resistance force is relatively weak compared to the two dominant forces.

The gravity force is highly predictable; it is always in the same direction (down) and always of the same magnitude - mass*9.8 N/kg. The tension force is considerably less predictable. Both its direction and its magnitude change as the bob swings to and fro. The direction of the tension force is always towards the pivot point. So as the bob swings to the left of its equilibrium position, the tension force is at an angle - directed upwards and to the right. And as the bob swings to the right of its equilibrium position, the tension is directed upwards and to the left. The diagram below depicts the direction of these two forces at five different positions over the course of the pendulum's path.

that's what I know so far

8 0
3 years ago
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