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OverLord2011 [107]
4 years ago
14

¿Cuál es el rango de frecuencias comprendido entre las longitudes de onda de 220 nm, 350 nm,

Physics
1 answer:
olchik [2.2K]4 years ago
3 0

Answer:

f1 = 1.36*10^15 Hz

f2 = 8.57*10^14 Hz

f3 = 3.75*10^14 Hz

f4 = 8.57*10^13 Hz

Explanation:

To know which are the frequency ranges of the wavelengths you use the following formula:

c=\lambda f\\\\f=\frac{c}{\lambda}

c: speed of light = 3*10^8m/s

λ: wavelength = 220nm, 350nm, 800nm, 3500nm

f: frequency of the wave

You calculate f for each wavelength, furthermore, you add the kind of electromagnetic wave:

λ1 = 220nm = 220*10^-9 m

f=\frac{3*10^8m/s}{220*10^{-9}m}=1.36*10^{15}Hz   ULTRAVIOLET

λ2 = 350nm = 350*10^-9 m

f=\frac{3*10^8m/s}{350*10^{-9}m}=8.57*10^{14}Hz   VISIBLE LIGHT

λ3 = 800nm = 350*10^-9 m

f=\frac{3*10^8m/s}{800*10^{-9}m}=3.75*10^{14}Hz   INFRARED    

λ4 = 3500nm = 350*10^-9 m

f=\frac{3*10^8m/s}{3500*10^{-9}m}=8.57*10^{13}Hz   MICROWAVE - INFRARED

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A car is stopped at a traffic light. It then travels along a straight road so that its distance from the light is given by x(t)=
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(c) after starting from rest, the car will be at rest again in 20 s

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v = 6(8) - 0.3(8²) = 28.8 m/s

(c) the velocity is zero at dx / dt = 0

6t - 0.3t² = 0

t(6 - 0.3t) = 0

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t= 0       or    t =  20 s

After starting from rest, the car will be at rest again in 20 s

6 0
3 years ago
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