Answer : The temperature of the chloroform will be, 
Explanation :
First we have to calculate the mass of chloroform.

conversion used : 
Now we have to calculate the temperature of the chloroform.
Formula used :

where,
q = amount of heat or energy = 1.46 kJ = 1460 J (1 kJ = 1000 J)
= specific heat capacity = 
m = mass of substance = 110.958 g
= final temperature = ?
= initial temperature = 
Now put all the given values in the above formula, we get:


Now we have to convert the temperature from Kelvin to Fahrenheit.
The conversion used for the temperature from Kelvin to Fahrenheit is:

As we know that,
or, 

...........(1)
Now put the value of temperature of Kelvin in (1), we get:


Therefore, the temperature of the chloroform will be, 
Answer:
2. Copper (II) carbonate plus sulfuric acid produces copper (II) sulfate and carbon dioxide and water.
- We need the "II" after copper to specify what charge it is. It's +2 because carbonate is -2.
3. Calcium hydroxide plus carbon dioxide gas produces calcium carbonate and water.
Answer: Protons
WHY?
Changing electrons will only result in the same element having different charges and hence, changing it's chemical properties.
Changing neutrons will not change an element but it will result in an isotope forming instead. (Isotopes are elements of the same type with different neutron numbers.)
However, changing the proton number would immediately change the nucleus composition, resulting in a change in element with a negative charge as there are more electrons than protons. This results in a expansion in valance electrons's distance from the nucleus. This results in a change in chemical properties of the element.
Therefore, a change in Protons is the answer.
Answer:
The balanced equation is:
2 HNO3 + Mg ---> Mg(NO3)2 + H2
From the equation, we can see that we need twice the moles of HNO3 than the moles of Mg
Moles of Mg:
Molar mass of Mg = 24 g/mol
Moles = Given mass / Molar Mass
Moles of Mg = 4.47 / 24 = 0.18 moles (approx)
Hence, 2(moles of Mg) = 0.36 moles of HNO3 will be consumed
Number of moles of HNO3 after the reaction is finished is the number of unreacted moles of HNO3
Unreacted moles of HNO3 = Total Moles - Moles consumed
Unreacted moles of HNO3 = 0.64 moles (approx)
Since we approximated the value of moles of Mg, the value of remaining moles of HNO3 will also be approximate
From the given options, we can see that 0.632 moles is the closest value to our answer
Therefore, 0.632 moles will remain after the reaction