Answer:
9.55 grams of SiO2
Explanation:
If the mass you mean by grams:
0.159 mole x 60.08 g (Periodic table by adding both elements)
Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:
9.55 grams of SiO2
Answer:
39.1 °C
Explanation:
Recall the equation for specific heat:

Where q is the heat, m is the mass, c is the specific heat of the substance (in this case water), and delta T is the change in temperature.
You should know that the specific heat of water is 1 cal/g/C.
Using the information in the question:

The final temperature is about 39.1 °C.
Answer : 1.12 grams
Yo find the mass of the sample, you take the increased mass and subtract the original mass.
6.130 - 5.010 = 1.12
Answer:
= 61.25 g
= 88.75 g
Explanation:
=
= 50 g
⇒
=
= 1.25 (moles)
2NaOH + H2SO4 ⇒ Na2SO4 + 2H2O
2 : 1 : 1 : 2
1.25 (moles)
⇒
= 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒
= 0.625 × 98 = 61.25 g
= 1.25 × 1 ÷ 2 = 0.625 (moles) ⇒
= 0.625 × 142 = 88.75 g