1. A body has a velocity of 72 km/hr. Find its value in m/s.
1 answer:
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Answer:
The amplitude of the oscillation is 2.82 cm
Explanation:
Given;
mass of attached block, m = 4.1 kg
energy of the stretched spring, E = 3.8 J
period of oscillation, T = 0.13 s
First, determine the spring constant, k;
where;
T is the period oscillation
m is mass of the spring
k is the spring constant
Now, determine the amplitude of oscillation, A;
where;
E is the energy of the spring
k is the spring constant
A is the amplitude of the oscillation
Therefore, the amplitude of the oscillation is 2.82 cm