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Bogdan [553]
3 years ago
6

Which sublevel would have electrons with the highest energy? A) 5s B) 4s C) 4d D) 4p

Chemistry
1 answer:
olya-2409 [2.1K]3 years ago
6 0
It’s D, you can tell because there electrons w the highest energy it would be faster
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1.The Tyndall effect cannot be detected in colloids.
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An object that has the ability to do work has __________ energy. (4 points)
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A hydrocarbon with general formaul cxhy is burned completely in air yielding 0.18 g of water and 0.44 g of carbon dioxide. Which
Savatey [412]

Answer:

CH2

Explanation:

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Fuel + Oxygen—-> Water + Carbon iv oxide

We can get the formula through calculations as follows.

From the mass of carbon iv oxide produced, we can get the number of moles of carbon produced. We first divide the mass by the molar mass of carbon iv oxide. The molar mass of carbon iv oxide is 44g/mol

The number of moles of carbon iv oxide is 0.44/44 = 0.01

Since there is only one carbon atom in CO2, the number of moles of carbon is same as above I.e 0.01 moles

From the number of moles of water, we can get the number of moles of hydrogen. To get the number of moles of water, we need to divide the mass of water by its molar mass. Its molar mass is 18g/mol. The number of moles here is thus 0.18/18 = 0.01moles

But there are 2 atoms of hydrogen in 1 mole of water and thus, the number of moles of hydrogen is 2 * 0.01= 0.02moles

The empirical formula can be obtained by dividing the number of moles of each by the smallest which is that of 0.01

H = 0.02/0.01 = 2

C = 0.01/0.01 = 1

From the calculations, x = 1 and y = 2

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8 0
4 years ago
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Calculate the boiling point of water if the atmospheric pressure is 630 mmhg
Mumz [18]

The boiling point of water can be calculated by the equation:

Where:

P = Pressure in mm Hg

Po = Atmospheric pressure in mm Hg

ΔH= heat of vaporization in kJ/mol

R = Ideal Gas Constant (J/mol-K)

To = normal boiling point in Kelvin

T = boiling point of water (K)

Our known values are:

P = 630 mm Hg

Po = 760 mm Hg

ΔH = 40.66 kJ/mol = 40.66×1000 =40660

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To = 373 K

Putting these values in the equation,

ln \frac{P_{0}}{P}= \frac{\Delta H}{R}(\frac{1}{T}-\frac{1}{T_{0}})

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Solving the equation will give:

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4 0
4 years ago
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