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nirvana33 [79]
3 years ago
7

Silicon is a metalloid element commonly found in Earth's crust. It helps form many different compounds, which have a variety of

different properties and applications.
One type of silicon-containing minerals is asbestos. Asbestos is resistant to heat and electricity, leading to its widespread use in manufacturing and the construction industry. Asbestos insulates buildings and makes them fire resistant. However, despite its usefulness, exposure to asbestos fibers or dust carries serious health risks that can cause respiratory disease or cancer.

Another silicon-containing compound is orthosilicic acid. Unlike asbestos, orthosilicic acid seems to benefit human health. This compound readily dissolves in water and is biologically stable enough to be used in the human body. Scientists have found evidence that orthosilicic acid plays an active role in the maintenance of strong bones.

The information above shows that silicon has both beneficial and detrimental effects on the human body. Given this information, think about other examples of materials or substances that can be both beneficial and detrimental at the same time. Research and write about two examples. Be sure to provide evidence to support your point of view.
Chemistry
1 answer:
sergey [27]3 years ago
8 0
The third one the answer is the third one
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How many grams of oxygen are required to burn 0.10mole of c3h8?
Anastaziya [24]
1mol—44g/mol
0.10mol—x
x=0.10*44
x=4.4 g
8 0
3 years ago
Which molecule would provide the most accurate value for the bond length of a nitrogen-nitrogen double bond
vredina [299]

Answer:

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Explanation:

7 0
3 years ago
EQUILIBRIUM Two moles of compound P were placed in a vessel. The vessel was heated and compound P was partially decomposed to pr
Reika [66]

As given:

Initial moles of P taken = 2 mol

the products are R and Q

at equilibrium the moles of

R = x

total moles =  2 + x/2

Let us check for each reaction

A) P <-> 2Q+R

Here if x moles of P gets decomposed it will give 2x moles of Q and x moles of R

So at equilibrium

moles of P left = 2- x

moles of Q = 2x

moles of R = x

Total moles = (2-x) + 2x + x = 2 +2x

B) 2P <-> 2Q+R

Here x moles of P will give x moles of Q and x/2 moles of R

So at equilibrium

moles of P left = 2- x

moles of Q = x

moles of R = x/2

Total moles = (2-x) + x + x/2 = 2 + x/2

C) 2P <-> Q+R

Here x moles of P will give x/2 moles of Q and x/2 moles of R

So at equilibrium

moles of P left = 2- x

moles of Q = x /2

moles of R = x/2

Total moles = (2-x) + x + x = 2

D) 2P <-> Q+2R

Here x moles of P will give x/2 moles of Q and x moles of R

So at equilibrium

moles of P left = 2-x

moles of Q = x/2

moles of R = x

Total moles = (2-x) + x/2 + x = 2 + x/2

3 0
3 years ago
For the following reaction, 42.2 grams of potassium hydrogen sulfate are allowed to react with 21.4 grams of potassium hydroxide
ASHA 777 [7]

Answer:

53.99g

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

KHSO4(aq) + KOH(aq) —> K2SO4(aq) + H2O(l)

Step 2:

Determination of the masses of KHSO4 and KOH that reacted and the mass of K2SO4 produced from the balanced equation.

This is illustrated below:

Molar mass of KHSO4 = 39 + 1 + 32 + (16x4) = 136g/mol

Mass of KHSO4 from the balanced equation = 1 x 136 = 136g

Molar mass of KOH = 39 + 16 + 1 = 56g/mol

Mass of KOH from the balanced equation = 1 x 56 = 56g

Molar mass of K2SO4 = (39x2) + 32 + (16x4) = 174g/mol

Mass of K2SO4 from the balanced equation = 1 x 174 = 174g.

From the balanced equation above, 136g of KHSO4 reacted with 56g of KOH to produce 174g of K2SO4

Step 3:

Determination of the limiting reactant. This is illustrated below:

From the balanced equation above, 136g of KHSO4 reacted with 56g of KOH.

Therefore, 42.2g of KHSO4 will react with = (42.2 x 56)/136 = 17.38g of KOH.

From the above calculations, we can see that only 17.38g out of 21.4g of KOH given was needed to react completely with 42.2g of KHSO4.

Therefore, KHSO4 is the limiting reactant and KOH is the excess reactant.

Step 4:

Determination of the maximum mass of K2SO4 produced from the reaction.

In this case, the limiting reactant will be used as all of it is used up in the reaction. The limiting reactant is KHSO4 and the maximum amount of K2SO4 produced can be obtained as follow:

From the balanced equation above, 136g of KHSO4 reacted to produce 174g of K2SO4.

Therefore, 42.2g of KHSO4 will react to produce = (42.2 x 174)/136 = 53.99g of K2SO4.

Therefore, the maximum amount of K2SO4 produced is 53.99g.

8 0
3 years ago
Group 1 elements have an average electronegativity of 0.84 (not
sergey [27]

A) The bond that will be formed by these elements is : <u>Ionic Bond </u>

B) Group 1 elements Gives up its electron to Group 17 elements

<h3><u /></h3><h3><u>Electronegativity values </u></h3>

From the electronegativity values given in the question group 17 elements with an electronegativity value of 2.99 are more electronegative than group 1 elements with a value of 0.84. Therefore they accept electron transfer from group 1 elements.

The acceptance of electrons from group 17 elements leads to formation of an ionic bond between group 1 and group 17.

Hence we can conclude that the bond that will be formed by these elements is Ionic bond  and Group 1 elements gives up its electron to group 17 elements.

Learn more about Ionic bonds : brainly.com/question/13526463

7 0
2 years ago
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