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RideAnS [48]
3 years ago
6

Why does the light from the touch reach upto only certain distance

Physics
1 answer:
ad-work [718]3 years ago
6 0
It is also likely (but not certain) that the photons will be absorbed by atoms. ... Light particles( or photons) never”run out” or loose their energy, so they can go an infinite distance, or until it reaches an object, that reflects the light or obsorbs it. Ie, a planet, or a mirror.
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. A 225-kg crate is pushed horizontally with a force of 710 N. If the coefficient of friction is 0.20, calculate the acceleratio
xz_007 [3.2K]

The acceleration of the crate is 1.196 m/s².

<h3>What is acceleration?</h3>

This can be defined as the rate of change of velocity.

To calculate the acceleration of the crate, we use the formula below.

Formula:

  • a = (F-mgμ)/m................. Equation 1

Where:

  • a = acceleration of the crate
  • m = mass of the crate
  • F = Force applied to the crate
  • μ = Coefficient of friction

From the question,

Given:

  • m = 225 kg
  • F = 710 N
  • g = 9.8 m/s²
  • μ = 0.20

Substitute the values above into equation 1

  • a = [710-(225×9.8×0.20)]/225
  • a = (710-441)/225
  • a = 269/225
  • a = 1.196 m/s²

Hence, The acceleration of the crate is 1.196 m/s²

Learn more about acceleration here: brainly.com/question/460763



4 0
2 years ago
The vertical displacement of an ocean wave is described by the function, y = A sin(ωt - kx). k is called the wave number (k = 2π
MrMuchimi

Answer:

Explanation:

a ) y = A sin(B)  ; here B is the phase of the wave which moves so that it remains constant

ωt - kx = constant

differentiating on both sides

ωdt - kdx =0

ωdt =   kdx

dx / dt = ω / k

wave velocity = ω / k

b ) ω = 14.5 rad / s ,

k = 18 rad / m

wave velocity = ω / k

= 14.5 / 18

= .805 m /s

80.5 cm / s

c )

Amplitude = A

= 9.5 m

4 0
3 years ago
What would be the relative difference between the currents required by a 60W lightbulb and a
anygoal [31]

The current required by the 60W bulb is three-fifths that required by the 110W bulb

<h3>Electrical Power</h3>
  • Electrical power is defined as the amount of electrical work done per second
  • Power = electrical work done in joules/time taken in seconds

The formula for calculating power is as follows:

  • P = IV = V²/R = I²R

Assuming the voltage across the light bulbs is the same

From the formula, P = IV;

I = P/V

For the 60 W bulb

I₁ = 60/V

For the 100W bulb

I₂ = 100/V

Taking ratios of the currents:

I₁/I₂ = {60/V}/{`100/V}

I₁/I₂ = 3/5

Therefore, the current required by the 60W bulb is three-fifths that required by the 110W bulb

Learn more about electrical power and currents at: brainly.com/question/12822995

4 0
3 years ago
Sunlight has its maximum intensity at a wavelength of 4.83 x 10'm; wha energy does this correspond to in e?
Lera25 [3.4K]

Answer:

E = 2,575 eV

Explanation:

For this exercise we will use the Planck equation and the relationship of the speed of light with the frequency and wavelength

     E = h f

     c = λ f

Where the Planck constant has a value of 6.63 10⁻³⁴ J s

Let's replace

    E = h c / λ

Let's calculate for wavelengths

    λ = 4.83 10-7 m     (blue)

    E = 6.63 10⁻³⁴ 3 10⁸ / 4.83 10⁻⁷

    E = 4.12 10-19 J

The transformation from J to eV is 1 eV = 1.6 10⁻¹⁹ J

    E = 4.12 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

    E = 2,575 eV

5 0
4 years ago
In flight, a rocket is subjected to four forces; weight, thrust, lift, and drag. Forces are vector quantities that have both a m
Flura [38]

Answer:

thrust

Explanation:

4 0
3 years ago
Read 2 more answers
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