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umka21 [38]
3 years ago
11

Which of the following statements is/are true? I: The conjugate acid of C6H5NH2 is C6H5NH3+ II: An acid with Ka = 1x10−3 is stro

nger than an acid with Ka = 1x10−4 III: A strong acid will be completely dissociated at equilibrium A) Only I B) Only II C) I and III D) II and III E) I, II, and III
Chemistry
1 answer:
Anna [14]3 years ago
5 0

Answer:

E. I, II, and III.

Explanation:

I. C6H5NH2 + H2O --> C6H5NH3^+ + OH-

C6H5NH2 is a weak base means it is a good proton donor (strong conjugate acid).

II. Any aqueous acid with a pKa value of less than 0 is almost completely deprotonated and is considered a strong acid.

pka1 = - log[1 x 10^-3]

= 2

pka1 = - log[1 x 10^-4]

= 3

pka1 is a stronger acid.

III. A strong acid will be completely dissociated at equilibrium.

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Using the equations 2 Sr(s) + O₂ (g) → 2 SrO (s) ∆H° = -1184 kJ/mol SrO (s) + CO₂ (g) → SrCO₃ (s) ∆H° = -234 kJ/mol CO₂ (g) → C(
kkurt [141]

<u>Answer:</u> The \Delta H^o_{rxn} for the reaction is 72 kJ.

<u>Explanation:</u>

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction follows:

2SrCO_3(s)\rightarrow 2Sr(s)+2C(s)+3O_2(g)      \Delta H^o_{rxn}=?

The intermediate balanced chemical reaction are:

(1) 2Sr(s)+O_2(g)\rightarrow 2SrO(s)    \Delta H_1=-1184kJ

(2) SrO(s)+CO_2(g)\rightarrow SrCO_3(s)     \Delta H_2=-234kJ      ( × 2)

(3) CO_2(g)\rightarrow C(s)+O_2(g)     \Delta H_3=394kJ    ( × 2)

The expression for enthalpy of the reaction follows:

\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[2\times (-\Delta H_2)]+[2\times (\Delta H_3)]

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times (-1184))+(2\times -(-234))+(2\times (394))]=72kJ

Hence, the \Delta H^o_{rxn} for the reaction is 72 kJ.

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2 years ago
Help please thanks you
scoundrel [369]

Explanation:

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