From the calculation, the percentage of water in the sodium hydroxide sample is 7%.
<h3>What is neutralization?</h3>
The term neutralization has to do with the reaction between an acid and a base to yiled salt and water.
Now we have to apply the titration formula;
CAVA/CBVB = NA/NB
CA = concentration of acid
CB = concentration of base
VA = volume of acid
VB = volume of base
NA = number of moles of acid
NB = number of moles of base
The reaction equation is; HCl + NaOH ----->NaCl + H2O
CAVANB = CBVBNA
CB = CAVANB /VBNA
CB = 34.9 * 0.2 M * 1/10 * 1
CB = 0.698 M
Number of moles = Conncentration * volume
= 0.698 M * 100/1000 L = 0.0698 moles
Mass = Number of moles * molar mass
Mass = 0.0698 moles * 40 g/mol = 2.79 g
percent of NaOH = 2.79 g/ 3g * 100/1 = 93%
Percent of water = 100- 93 = 7%
Learn more about neutralization: brainly.com/question/15395418
