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rosijanka [135]
3 years ago
14

An organic compound (A) reacts with HCN to give (B). On hydrolysis of (B) in acidic medium gives (C). Compound (A) also produces

propane when treated with zinc-amalgam and HCl. Identify (A), (B) and (C) with reaction and give their IUPAC names.What product would you expect when A is treated with trichloromethane in alkaline medium.​
Chemistry
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

Hydrolic Acid

Explanation:

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A red blood cell placed in saline solution will shrink.<br> True or false? Explain please?
Scorpion4ik [409]
Yes a red blood cell placed in a sline solution shrinks because of the process of osmosis.
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24 POINTS!!!!!!!!!!!!!!!!!!!!!!!!!!!
erastovalidia [21]
I'd say b, but i'm not 100 percent sure.<span />
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A chemical might be used to melt ice if it raises the temperature of the ice. This best type reaction to accomplish this would b
Setler79 [48]
<h2>Answer:</h2>

B) endothermic reaction.

<h2>Explanation:</h2>

Melting of ice is endothermic because it is taking heat from the environment, feeling cold, because it requires energy to break the ice bonds. It's also why you feel cold when wet it takes energy to evaporate water. The ice absorbs the energy from the environment. Its internal potential energy increases, therefore, it's endothermic. It also increases the entropy of reaction.

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3 years ago
If a 32.5 mL of a 15.1 M HCl solution was diluted to 3.25 L with water, what is the final concentration?
user100 [1]

Answer:

The final concentration is 0,151 M.

Explanation:

A dilution consists of the decrease of concentration of a substance in a solution (the higher the volume of the solvent, the lower the concentration).

We convert the unit of volume in L into ml: 3,25 x 1000= 3250 ml

We use the formula for dilutions:

C1 x V1 = C2 x V2

C2= (C1 xV1)/V2

C2= (32, 5 ml x 15, 1 M)/ 3250 ml

<em>C2=0,151 M</em>

8 0
3 years ago
What will happen to the pH of a buffer if acid/base ratio is increased by 100?
sp2606 [1]

Answer:

It will decrease by 2 units.

Explanation:

The Henderson-Hasselbalch equation for a buffer is

pH = pKa + log(base/acid)

Let's assume your acid has pKa = 5.

(a) If the base: acid ratio is 1:1,

pH(1) = 5 + log(1/1) = 5  + log(1) = 5 + 0 = 5

(b) If the base: acid ratio is 1:100,

pH(2) = 5 + log(1/100) = 5  + log(0.01) = 5 - 2 = 3

(c) Difference

ΔpH = pH(2) - pH(1) = 5 - 3 = -2

If you increase the acid:base ratio to 100:1, the pH will decrease by two units.

4 0
3 years ago
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