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Paha777 [63]
3 years ago
7

Explain why the ionic radii for S^-2 is larger than O^-2?

Chemistry
1 answer:
notsponge [240]3 years ago
7 0

Answer:

When comparing two ions, gaining the same electrons, atomic radii, you can follow the same general rule as regular ionic radius.

Explanation:

In general, Sulfur has a larger atomic radius than Oxygen, as it is lower on the periodic table. Since they both are gaining the same amount of electrons, the trend still applies

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Determine the moles of oxygen gas (O2) needed to completely react with 1.975 moles of hydrogen gas (H2).
Pavlova-9 [17]

Answer:

0.9875 mole O₂

Explanation:

Rxn => H₂ + ¹/₂O₂ => H₂O

from above reaction, 1 mol H₂ requires ¹/₂ mol O₂ then 1.975 mol H₂ requires   ¹/₂(1.975 mol)O₂ or 0.9875 mol O₂.

6 0
3 years ago
How does the sharing of bonding electrons in a molecule of Cl2 compare to that in a molecule of HCI?
Ronch [10]
The chlorine atom bonds through covalent bond to obtain an octet structure so two atoms of 2,8,7 come together and HCl consists of both metal and nonmetal which is the the covalent bonding principle so H and Cl share the 8 valence electrons to obtain an octet structure.
8 0
4 years ago
The atom of chlorine has several valence electrons in its
Ivan
The atom of chlorine has <span>several valence electrons in its</span> valence electrons are in the third shell.
8 0
3 years ago
Hi please help, tysm. Answer is in nm
boyakko [2]

Answer:

268 nm

Explanation:

The equation needed to find wavelength is:

E = hc / w

In this equation,

-----> E = energy (J)

-----> h = Planck's Constant (6.626 x 10⁻³⁴ J*s)

-----> c = speed of light (3.0 x 10⁸ m/s)

-----> w = wavelength (m)

To find the wavelength, you can plug the given values into the equation and simplify. Then, you can convert meters to nanometers.

E = hc / w

7.41 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J*s)(3.0 x 10⁸ m/s) / w     <---- Input given values

7.41 x 10⁻¹⁹ J = 1.9878 x 10⁻²⁵ / w                                   <----- Simplify

(7.41 x 10⁻¹⁹ J) x w = 1.9878 x 10⁻²⁵                                <----- Rearrange

w = 2.68 x 10⁻⁷ m                                                          <----- Simplify

 2.68 x 10⁻⁷ m           1 x 10⁹ nm
----------------------  x  ----------------------  = 268 nm
                                         1 m

3 0
2 years ago
A vessel of volume 100 cm3 contains 0.25 mol o2 and 0.034 mol co2 at 10.0c. Calculate the partial pressure of each component and
Artyom0805 [142]

Answer: The partial pressure of oxygen is 76.56 atm , partial pressure of carbon dioxide is 10.44 atm and the total pressure is 87 atm.

Explanation:

According to the ideal gas equation:'

PV=nRT

P = Pressure of the gas = ?

V= Volume of the gas = 100cm^3=0.1L 1L=1000cm^3

T= Temperature of the gas = 10°C = 373 K      

R= Gas constant = 0.0821 atmL/K mol

n=  moles of gas= 0.25 +0.034 = 0.284 moles

P=\frac{nRT}{V}=\frac{0.284\times 0.0821\times 373}{0.1}=87atm

x_{O_2} = mole fraction of oxygen=\frac{\text {moles of }O_2}{\text {moles of }O_2+\text{moles of }CO_2}=\frac{0.25}{0.25+0.034}=0.88,  

x_{CO_2} =mole fraction of carbon dioxide=\frac{\text {moles of }CO_2}{\text {moles of }O_2+\text{moles of }CO_2}=\frac{0.034}{0.25+0.034}=0.12

partial pressure of oxygen = p_{O_2}=x_{O_2}\times P=0.88\times 87=76.56atm

partial pressure of carbon dioxide= p_{CO_2}=x_{CO_2}\times P=0.12\times 87=10.44atmatm

The partial pressure of oxygen is 76.56 atm , partial pressure of carbon dioxide is 10.44 atm and the total pressure is 87 atm.

8 0
3 years ago
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