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julia-pushkina [17]
2 years ago
10

Both natural processes and human activity are causing some of Earth's permanent

Physics
1 answer:
wlad13 [49]2 years ago
8 0

Answer:

The water will get more warm fresh water

Explanation:

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Is lateral shift or lateral displacement same ?
xxMikexx [17]

Answer:

When a ray of light passes through a glass slab of a certain thickness, the ray gets displaced or shifted from the original path. This is called lateral shift/displacement.

Explanation:

.

7 0
3 years ago
Is the distance a baseball travels in the air after being hit distance a baseball travels in the air after being hit a discrete
Nookie1986 [14]

Answer:

Continuous random variable

Explanation:

The distance that baseball travels after being hit is a random variable and it assume any real value defined on the sample space.

The distance is measurable and thus is continuous random variable because continuous variable cannot be counted but could be measured.

3 0
3 years ago
PREDICT
Vikentia [17]
Well the block will still have to deal with gravitational force. So here’s my prediction: Although the block is being dropped at different heights it will accelerate at the same speed no matter what and this is due to the earths gravitational energy (9.8m/s^2 or roughly 10m/s^2) so the only thing that will change is the height that the object is dropped.
6 0
3 years ago
Read 2 more answers
Which force causes send dunes? A. Rivers B. Ice C. Wind D. Gravity
lutik1710 [3]
Wind I believe cause it carries the sand to different places
5 0
3 years ago
Read 2 more answers
A cyclist moving with a constant velocity of 6.0 m/s forward passes a car that is just starting. If the car has a constant accel
sergiy2304 [10]

After 6 seconds, the car will surpass the cyclist.

<h3><u>Explanation:</u></h3>

The speed of the cyclist = 6 m/s.

Let after time t sec, the car will overtake the cyclist.

So, distance covered by the cyclist in t sec = 6t m

Initial velocity of the car is 0 m/s, because the car is just starting.

Acceleration of the car =2 m/s^2.

Final velocity of the car =6 m/s.

So to cover the distance 6t, the time required by the car = \frac{1}{2} \times a \times t^2 = \frac{1}{2} \times 2 \times t^2

6t = \frac{1}{2} \times 2 \times t^2\\6t = t^2

t =6 sec

So, after 6 seconds, the car will surpass the cycle.  

6 0
3 years ago
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