The amplitude of the wave is 0.022m
<h3 /><h3>How to solve solve for the amplitude</h3>
<u>Given data</u>
period T= 25.0ms = 0.025s
speed of 30.0 m/s
t = 0
x = 0
transverse position of 2.00cm = 0.02m
<h3 />
wave equation is = y ( x ) = A cos ( ωx + ∅ )
since:
t = 0
x = 0
0.02 = A cos ( 0 + ∅ )
0.02 = A cos ( ∅ )
speed = v ( x )= 2.0 m/s = d y ( x ) / d x
- 2 = - Aω sin ( ∅ )
dividing the equations as below gives
- Aω sin ( ∅ ) / A cos ( ∅ )
- ω tan ( ∅ ) = - 2 / 0.02
ω tan ( ∅ ) = 100
ω = 2 * pi * f = 2 * pi / T = 2 * pi / 0.025 = 80 * pi
tan ( ∅ ) = 100 /( 80* pi )
tan ( ∅ ) = 0.398
∅ = 0.3787 rad
Amplitude = 0.3787 / cos ∅
Amplitude = 0.022m
Read more on amplitude of wave here: brainly.com/question/19036728
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