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zhannawk [14.2K]
3 years ago
10

Bill and Nageen have each built an electric motor and they are testing them by having them lift boxes. Bill's motor lifts a box

0.35 metres in 2 seconds. Nageen's motor lifts the same box 0.35 metres in 1.8 seconds. Whose motor has applied more power to the box?
Physics
1 answer:
photoshop1234 [79]3 years ago
5 0

Answer:

Bill's motor power: W_B = F x S / T = F x 0.35 / 2= 0.175F

Nageen's motor power: W_N = F x S / T = F x 0.35 / 1.8 = 0.194F

=> 0.194F > 0.175F => Nageen's motor applied more power to the box than Bill's motor.

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Answer:

32.176 ft/s²

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Explanation:

Data provided in the question:

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and,

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78979.4 mi/hr = \frac{\textup{78979.4}\times\textup{5280}}{\textup{1}\times\textup{3600}^2}

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b) In m/s²

Now,

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thus,

we have from 1

32.17 ft/s² =  \frac{\textup{32.17}\times\textup{0.3048}}{\textup{1}\times\textup{1}^2}

or

78979.4 mi/hr = 32.176 ft/s²  = 9.807 m/s²

7 0
3 years ago
Mr John slides from rest a height of 12.2m down a smooth plane inclined at an angle 30° to the horizontal,.. calculate the dista
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24.4 m

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4 0
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