It takes 100 n to move a box 10 meters in 5 seconds. how much power is required?

Physics

2 answers:

mylen [45]3 years ago

8 0

Answer: 200 w in apex

I am Lyosha [343]3 years ago

6 0

<span>Power = Work / Time
Work = Force * Distance

Force is measured in Newtons, so 100 N is the force in this situation.
Distance in this scenario is 10 m. And time is 5 s.

Inserting known values into the formulas:
Work = 100 N * 10 m = 1000 J
(J = Joules, the equivalent of "Newton-meters")

Power = 1000 J / 5 s = 200 W
(W = Watts, the equivalent of 1 Joule / second)

In summary, 200 W of power are required for this situation.</span>

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Compare and contrast the energy transfer of a roller coaster to that of a pendulum

Softa [21]

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As a pendulum swings, its potential energy changes to kinetic energy and kinetic energy changes into potential energy. At the top more potential energy is present.

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1 year ago

A proton traveling at 17.6° with respect to the direction of a magnetic field of strength 3.28 mT experiences a magnetic force o

umka2103 [35]

Answer:

a) The proton's speed is 5.75x10⁵ m/s.

b) The kinetic energy of the proton is 1723 eV.

Explanation:

a) The proton's speed can be calculated with the Lorentz force equation:

$F = qv \times B = qvBsin(\theta)$ (1)

Where:

F: is the force = 9.14x10⁻¹⁷ N

q: is the charge of the particle (proton) = 1.602x10⁻¹⁹ C

v: is the proton's speed =?

B: is the magnetic field = 3.28 mT

θ: is the angle between the proton's speed and the magnetic field = 17.6°

By solving equation (1) for v we have:

$v = \frac{F}{qBsin(\theta)} = \frac{9.14 \cdot 10^{-17} N}{1.602\cdot 10^{-19} C*3.28 \cdot 10^{-3} T*sin(17.6)} = 5.75 \cdot 10^{5} m/s$

Hence, the proton's speed is 5.75x10⁵ m/s.

b) Its kinetic energy (K) is given by:

$K = \frac{1}{2}mv^{2}$

Where:

m: is the mass of the proton = 1.67x10⁻²⁷ kg

$K = \frac{1}{2}mv^{2} = \frac{1}{2}1.67 \cdot 10^{-27} kg*(5.75 \cdot 10^{5} m/s)^{2} = 2.76 \cdot 10^{-16} J*\frac{1 eV}{1.602 \cdot 10^{-19} J} = 1723 eV$