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2 years ago

An ion contains 54 electrons after its atom gained 1 electron to form a stable electron

Chemistry

1 answer:

zhuklara [117]2 years ago

3 0

Answer:

Iodine has an atomic number of 53 meaning 53 electrons and it gain 1 electron when reacting with a metal. We know the element is a non metal as is gains an electron

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Why does the atmosphere allow life on planet Earth

Marina86 [1]

Answer:

contains oxgen , hydrogen and water vapour

Explanation:

oxygen+hydrogen=water =to life

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3 years ago

Show

SIZIF [17.4K]

Answer: 0.9375 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Moles of solute}={\text{Molarity of the solution}}\times{\text{Volume of solution (in L)}}$ .....(1)

Molarity of $HCl$ solution = 0.75 M

Volume of $HCl$ solution = 25.0 mL = 0.025 L

Putting values in equation 1, we get:

$\text{Moles of} HCl={0.75}\times{0.025}=0.01875moles$

$CaCO_3(s)+2HCl(aq)\rightarrow CaCl_2(s)+CO_2(g)+H_2O(l)$

According to stoichiometry :

2 moles of $HCl$ require = 1 mole of $CaCO_3$

Thus 0.01875 moles of $HCl$ will require= $\frac{1}{2}\times 0.01875=0.009375moles$ of $CaCO_3$

Mass of $CaCO_3=moles\times {\text {Molar mass}}=0.009375moles\times 100g/mol=0.9375g$

Thus 0.9375 g of $CaCO_3$ is required to react with 25.0 ml of 0.75 M HCl

6 0

3 years ago

The temperature of a freezer started at 18şc. After cooling for a few hours, the freezer had a temperature of –12şc. What is the

andre [41]

20 minus 2 plus 1 equals negative -2000000

8 0

3 years ago

How many grams of copper would have the same number of atoms as 139.82 grams of argon

lianna [129]

Answer:

Lesson 3 Quiz ReturntoAssessmentList Part 1 of 4 - 4.0/ 8.0 Points Question 1 of ... in the balloon containing regular air D.Each balloon has an equal number of atoms. ... The purity of those pre-1982 pennies are really about 95% copper (5% zinc ... that had a mass of 3.11 grams, how many atoms of copper would you have?

Explanation:

7 0

3 years ago

Se disuelven 10 g de acido carbónico H2CO3 en 150 g de agua. Determina la concentración % m/m de esa disolución?

sergey [27]

The question is: 10 g of carbonic acid H2CO3 are dissolved in 150 g of water. Determine the% m / m concentration of that solution?

Answer: The% m / m concentration of that solution is 6.66%.

Explanation:

Given: Mass of solute = 10 g

Mass of solvent = 150 g

Formula used to calculate the %m/m is as follows.

$Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100$

Substitute the values into above formula as follows.

$Percent (m/m) = \frac{mass of solute}{mass of solvent} \times 100\\= \frac{10 g}{150 g} \times 100\\= 6.66%$

Thus, we can conclude that the% m / m concentration of that solution is 6.66%.

6 0

3 years ago