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mart [117]
3 years ago
9

The experimental evidence that electrons could act as waves was based on quantized wavelengths and diffraction pattern evidence.

True or False???
Chemistry
2 answers:
koban [17]3 years ago
8 0

Answer: -

When electrons are fired at an element, the resulting interference pattern is called electron diffraction.

Electrons get scattered on hitting and they are observed via a luminescent screen. The pattern of scattered electrons is consistent with wave behavior like that of X rays.

The experimental evidence that electrons could act as waves was based on quantized wavelengths and diffraction pattern evidence is therefore correct.

o-na [289]3 years ago
6 0

Answer:

True

Explanation:

There was a theory proposed by the French physicist <u>Louis de Broglie</u> in 1923. This theory basically states that particles that are studied in quantum mechanics (for example, electrons and light), exhibit properties that can be seen when studying both particles, and waves. This theory was called Wave-Particle Duality.

When studying electrons, they were observed to behave like particles in certain experiments, however, in other experiments they also behaved how a wave would. We think of electrons as particles, which have mass, but they can also be diffracted like electromagnetic waves.

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The process that causes a spark to occur when the discharge wand is close to the Van de Graaff generator is similar to the proce
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Answer:

Lighter, positively charged particles form at the top of the cloud. Heavier, negatively charged particles sink to the bottom of the cloud. When the positive and negative charges grow large enough, a giant spark - lightning - occurs between the two charges within the cloud.

Explanation:

4 0
2 years ago
34. An electron in the 3d state of the hydrogen atom has a radial part of the wave function of the form A r2 exp(-r/3ao). What i
nikdorinn [45]

Answer: Option (e) is the correct answer.

Explanation:

Formula to calculate radius is as follows.

          p(r) = Ar(r^{2}e^{\frac{-r}{3a_{o}}}

                = Ar^{3}e^{\frac{-r}{3a_{o}}}

     \frac{dp(r)}{dr} = 0

            Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}} + Ae^{\frac{-r}{3a_{o}}}(3r^{2}) = 0

                     \frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}

                      = 3Ar^{2}e^{\frac{-r}{3a_{o}}}

                       r = 9a_{o}

Thus, we can conclude that most likely radius at which the electron would be found is 9a_{o}.

4 0
3 years ago
Oil flows upward in the wick of a lantern because of the liquid property called
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B
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7 0
3 years ago
Read 2 more answers
_Li + __F2 → _LIF<br> How do I balance this?
Semmy [17]

Answer:

 2Li   +   F₂    →    2LiF

Explanation:

The reaction expression is given as:

          Li   +   F₂    →     LiF

We are to balance the expression. In that case, the number of atoms on both sides of the expression must be the same.

 Let use a mathematical approach to solve this problem;

  Assign variables a,b and c as the coefficients that will balance the expression:

             aLi   +  bF₂    →     cLiF

Conserving Li: a  = c

                   F:  2b  = c

          let a = 1, c  = 1 and b  = \frac{1}{2}  

  Multiply through by 2;

        a  = 2, b = 1 and c  = 2

               2Li   +   F₂    →    2LiF

 

5 0
3 years ago
Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many boxes of B would be required to make 30
Iteru [2.4K]
Mass box C is 10+5. (So C is 15)

But if C was 30, how many times could you put B (5) into it?

30/5 = 6

You would need 6 boxes of B to make 30 grams of C.
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3 years ago
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