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mart [117]
2 years ago
9

The experimental evidence that electrons could act as waves was based on quantized wavelengths and diffraction pattern evidence.

True or False???
Chemistry
2 answers:
koban [17]2 years ago
8 0

Answer: -

When electrons are fired at an element, the resulting interference pattern is called electron diffraction.

Electrons get scattered on hitting and they are observed via a luminescent screen. The pattern of scattered electrons is consistent with wave behavior like that of X rays.

The experimental evidence that electrons could act as waves was based on quantized wavelengths and diffraction pattern evidence is therefore correct.

o-na [289]2 years ago
6 0

Answer:

True

Explanation:

There was a theory proposed by the French physicist <u>Louis de Broglie</u> in 1923. This theory basically states that particles that are studied in quantum mechanics (for example, electrons and light), exhibit properties that can be seen when studying both particles, and waves. This theory was called Wave-Particle Duality.

When studying electrons, they were observed to behave like particles in certain experiments, however, in other experiments they also behaved how a wave would. We think of electrons as particles, which have mass, but they can also be diffracted like electromagnetic waves.

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Answer: <em>Hopefully this helps! sorry if not. :))</em>

<em></em>

<em>Speed has a greater impact on mass because its increases in velocity have an exponentially greater impact on translational kinetic energy because kinetic energy is proportional to velocity squared. Doubling an object's mass would only double its kinetic energy, however doubling its momentum would quadruple its velocity.</em>

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2 years ago
Which element has 21 neutrons and 20 electrons?
mario62 [17]
Scandium has 21 neutrons
6 0
2 years ago
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What is the percent composition by mass of each element in Co(HSO4)2?
MrRissso [65]

Answer:

54.1 % Ca, 43.2 % O, 2.7% H

Explanation:

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As we don't have a mass of Ca(OH)₂ to find out the percentage composition, we consider that the question refers to 1 mol of compound.

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(2 / 74.08) . 100 = 2.7%

im a smart one

7 0
2 years ago
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Katen [24]

Answer:

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Explanation:

Hope this helps! :)

8 0
3 years ago
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