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2 years ago

A rod measures 17.2 inches. How many centimeters is this? [ ? ] cm

Chemistry

1 answer:

Rufina [12.5K]2 years ago

3 0

This problem is providing the length in inches of a rod and it is being required to convert it to centimeters. According to the following, the answer will be 43.7 cm:

<h3>Units conversion:</h3><h3 />

In science, we use units conversion to represent measurements in different types of units depending on a specific requirement. To do so, we use conversion factors based on equivalence statements, relating the required unit with the given one.

In this case, the equivalence statement between inches and centimeters is 2.54 cm = 1 in and we can use it to get the answer as shown below:

$17.2in*\frac{2.54cm}{1in} \\\\=43.7 cm$

Learn more about units conversion: brainly.com/question/13016491

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When placed in a 100mL cube shaped box a substance fills the cube and has a volume of 100 mL. When places in a 50mL tube that sa

Whitepunk [10]

There are five states of matter out of which we encounter three states of matter in our day today life

a) gas b) solid and c) liquid

the main difference between the three is of

a) Inter molecular forces of attraction

b) thermal energy

due to this

a) solid has high intermolecular forces and low thermal energy: thus they have fix shape and occupy fix volume

b) liquid has intermediate forces and medium themal energy. Thus they may have fixed volume and but no fix shape

c) gas has weak intermoelcular forces and high thermal energy. thus they have no fixed volume no fix shape

so in the given problem

the state of the substance D- Gas.

8 0

3 years ago

A gas starts at a volume of 23 L and a pressure of 1.23 atm. What is the new pressure if you

Anna71 [15]

Answer:

Explanation:

The new volume can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new volume

$V_2 = \frac{P_1V_1}{P_2} \\$

From the question we have

$V_2 = \frac{1.23 \times 23}{15} = \frac{28.29}{15} \\ = 1.886$

We have the final answer as

Hope this helps you

7 0

2 years ago

How many grams in 11.9 moles of sulfur? Avogadro’s number: 6.02x1023 atoms = 1 mole Molar mass of sulfur: 32.06 g sulfur = 1 mol

sergiy2304 [10]

Answer:

Mass = 0.37 g

Explanation:

Given data:

Number of moles of sulfur = 11.9 mol

Mass of sulfur in 11.9 mol = ?

Molar mass of sulfur = 32.06 g

Solution:

Number of moles = mass/molar mass

by putting values,

11.9 mol = mass/ 32.06 g/mol

Mass = 11.9 mol × 32.06 g/mol

Mass = 0.37 g

4 0

2 years ago

Which equation agrees with ideal gas law?

Julli [10]

Https://www.gstatic.com/education/formulas2/355397047/en/boyle_s_law.svg

8 0

2 years ago

How much energy is required to raise the temperature of 3 kg of iron from 20° C to 25°C? Use the table below and this equation:

ElenaW [278]

The energy required to raise the temperature of 3 kg of iron from 20° C to 25°C is 6,750 J( Option B)

<u>Explanation:</u>

Given:

Specific Heat capacity of Iron= 0.450 J/ g °C

To Find:

Required Energy to raise the Temperature

Formula:

Amount of energy required is given by the formula,

Q = mC (ΔT)

Solution:

M = mass of the iron in g

So 3 kg = 3000 g

C = specific heat of iron = 0.450 J/ g °C [ from the given table]

ΔT = change in temperature = 25° C - 20°C = 5°C

Plugin the values, we will get,

Q = 3000 g × 0.450 J/ g °C × 5°C

= 6,750 J

So the energy required is 6,750 J.

7 0

3 years ago

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