<u>Answer:</u> The amount of pure antifreeze that must be added is 6.4 gallons
<u>Explanation:</u>
We are given:
Percent of antifreeze given = 10 %
Amount of solution = 8 gallons
Let the amount of pure antifreeze be 'x'
Calculating the amount of pure antifreeze:
Let the amount of pure antifreeze added in the solution be 'y'
Percent of solution to be made = 50 %
So,
Hence, the amount of pure antifreeze that must be added is 6.4 gallons
The answer would be water , carbon dioxide and methane because they all contain more than one element.
Water-H2O
Carbon Dioxide-CO2
Methane-CH4
The balanced equation
for the reaction is:
6 HNCO(l) →
C3N3(NH2)3(l) + 3 CO2(g)
Convert amount of urea
from kg to moles
Molar Mass of urea = 60.06
g/mol so, 113 kg urea contains
113 kg / 60.06 = 1.88
mol urea
From balanced equation 6
moles of urea yields only 1 melamine, so divide the moles of urea by 6.
1.88 / 6 = 0.313 kmol
melamine
Now multiply 0.313 with
molar mass of melamine that is 126 g/mol
126 x 0.313 = 39.438 kg
Yield of overall
reaction is 73% so multiply 39.438 with 0.73
<span>39.438 x 0.73 = 28.799
kg is the answer</span>
Answer:
covalent bonding
Type of Bonding: Sulfur Dioxide is a process of covalent bonding, since Sulfur and Oxygen are both non-metals. The Sulfur is in the center surrounded by 2 Oxygen atoms.
Answer:
The value is 
Explanation:
From the question we are told that
The bond length is 
The bond dipole moment is 
Generally the dipole moment is mathematically represented as
Here Q is the partial negative charge on the bromine atom
So
=> 
=> 
Generally
1 electronic charge(e) is equivalent to 
So x electronic charge(e) is equivalent to
=> 
=>
