Here, DH = HF
x+3 = 3y
x = 3y-3 ----(I)
GH = HE
4x-5 = 2y+3
4x = 2y+8
Substitute value of x,
4(3y-3) = 2y+8
12y-12 = 2y+8
12y-2y = 12+8
10y = 20
y = 2
Now, substitute it in equation 1,
x = 3(2)-3
x = 6-3 = 3
So, your final answer is x=3 & y=2
Answer:false
Step-by-step explanation:no constant rate of change in y and x values
Answer:
2
Step-by-step explanation:
1st step: solve the exponential number
2x^2=4x
3x^2=9x
2nd step: rewrite the number sentence with the exponent solved
4x-8x+8 9x+27x-30
3rd step : solve
4x-8x=-4x 9x+27x=36x
-4x+8= 36x-30=
4 6
Step 4: See what least common multiples they have in common
4 LCM =2 * 2= 4 6 LCM= 2*3=6
So the LCM is 2
You are finding 3 1/6 - 1 5/6.
To solve, you should first change it so that the numerator of the first fraction is greater than the numerator of the second. Note that both have the same denominator (6). Subtract as usual:
3 1/6 = 2 7/6
2 7/6 - 1 5/6 = 1 2/6
1 2/6 is your answer.
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