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Novosadov [1.4K]
3 years ago
9

What was primarily responsible for the formation of a delta glacial erosion incrementation of sediment deposition of sediment ma

ss movement 3. Which event is the best example of erosion shale breaking apart as water freezes in its cracks dissolving of limestone to make a cave a pebble rolling along the bottom of a stream bedrock crumbling to form a residual soil

Physics
1 answer:
Ivanshal [37]3 years ago
3 0
First answer is 1. then second answer is 4.
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Under normal circumstances: _________
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Fetal Hb binds oxygen more tightly than adult Hb (not option a)

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A car increased its velocity to 62m/s in 10s starting from rest. Calculate the distance it covers during this time?
Roman55 [17]

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distance= velocity ×time

distance= 62×10

distance=620m

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3 years ago
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Two common ions of manganese are Mn2+ and Mn3+. Which binary ionic compound is likely to form? A) Mn2N3 B) MnBr4 C) MnCl D) MnO
meriva
Given that Oxygen has an oxidation state of  2 -, you can combine Mn 3+ with O 2- ions to form Mn2O3, and you can combine Mn 2+ with O 2- to form Mn2O2 which is MnO.

The other compounds imply oxidation states of N, Br and Cl that does not exist.

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3 years ago
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Scientists are studying a moving glacier. To monitor the flow of the glacier, they place a series of five markers, A, B, C, D, a
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4 0
3 years ago
1.Suppose someone pulls a cart up a ramp a distance of 85cm along the ramp with a force of 15N.
Drupady [299]

1. 12.75 J

Assuming that the force applied is parallel to the ramp, so it is parallel to the displacement of the cart, the work done by the force is

W=Fd

where

F = 15 N is the magnitude of the force

d = 85 cm = 0.85 m is the displacement of the cart

Substituting in the formula, we get

W=(15 N)(0.85 m)=12.75 J


2. 10.6 N

In this part, the cart reaches the same vertical height as in part A. This means that the same work has been done (because the work done is equal to the gain in gravitational potential energy of the object: but if the vertical height reached is the same, then the gain in gravitational potential energy is the same, so the work done must be the same).

Therefore, the work done is

W=Fd=12.75 J

However, in this case the displacement is

d = 120 cm = 1.20 m

Therefore, the magnitude of the force in this case is

F=\frac{W}{d}=\frac{12.75 J}{1.20 m}=10.6 N

3 0
3 years ago
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