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Shtirlitz [24]
3 years ago
14

A wire of diameter 1 mm has a resistance of 0.5 . What is the resistance of another wire of the same material and the same leng

th but of diameter 0.5 mm?
Physics
1 answer:
victus00 [196]3 years ago
8 0

The second wire has 1/2 the <u>radius</u> of the first wire.  

Now the area of a circle is (A =π r²) ... the area changes in proportion to the SQUARE of the circle's radius.

So if you cut both wires exactly perpendicular to their lengths, and look at the circular end where the cut is, the second wire has only 1/4 the cross-section AREA of the first wire.  Current in the second wire is trying to squeeze through a pipe that only has 1/4 the space to carry it.

The resistance of a piece of wire-2 is 4 times the resistance of a piece of wire-1 with the same length.

The resistance of wire-2 is (4 x 0.5 ohm) = <em>2 ohms</em> .

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The velocity of sound in air at 300C is approximately :
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The velocity of sound in at 300C is 511.3 m/s.

Explanation:

The equation that gives the speed of sound in ar as a function of the air temperature is the following:

v=(331.3+0.6T) m/s

where

T is the temperature of the air, measured in Celsius degrees

In this problem, we want to find the speed of sound in ar for a temperature of

T=300^{\circ}C

Substituting into the equation, we find:

v=331.3 + 0.6(300)=511.3 m/s

So, the velocity of sound in at 300C is 511.3 m/s.

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brainly.com/question/4899681

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Which of the following are scalar quantities?
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2 years ago
An 67-kg jogger is heading due east at a speed of 2.3 m/s. A 70-kg jogger is heading 61 ° north of east at a speed of 1.3 m/s. F
ololo11 [35]

Answer

given,

mass of jogger  = 67 kg

speed in east direction = 2.3 m/s

mass of jogger 2 = 70 Kg

speed  = 1.3 m/s  in  61 ° north of east.

jogger one

P_1 = m_1 v_1 \hat{i}

P_1 = 67 \times 2.3\hat{i}

P_1 = 154.1 \hat{i}

P_2 = m_2 v_2 \hat{i} +m_2 v_2 \hat{j}

P_2 = 70\times v cos \theta \hat{i} +70\times v sin \theta \hat{j}

P_2 = 70\times 1.3 cos 61^0 \hat{i} +70\times 1.3 sin 61^0\hat{j}

P_2 = 44.12\hat{i} +79.59\hat{j}

now

P = P₁ + P₂

P = 198.22 \hat{i} +79.59 \hat{j}

magnitude

P = \sqrt{198.22^2 + 79.59^2}

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\theta = tan^{-1}\dfrac{79.59}{198.22}

\theta = 21.87

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3 years ago
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