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Hunter-Best [27]
3 years ago
11

Why do people sweat .-.

Physics
2 answers:
Dominik [7]3 years ago
8 0
Because we have sweat glands in our skin and the reason is to decrease the body temperature
egoroff_w [7]3 years ago
8 0
It's perfectly normal to sweat<span>. </span>Sweating<span> plays an important health role because it helps maintain body temperature by cooling us down. When we're hot and we</span>sweat<span>, that moisture evaporates and cools us off a bit. ... It's also normal for </span>people<span>to </span>sweat<span> when they're nervous because emotions can affect the </span>sweat<span> glands.</span>
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The ratio of the focal length of a lens to it's diameter is the​
user100 [1]

Answer:

The f-ratio describes the relationship between the lens diameter and the focal length and is calculated by dividing the focal length by the diameter of the lens. For example, if a lens were to have a focal length of 50mm and a diameter of 10mm, then the f-ratio would be 50mm/10mm=5 or otherwise referred to as f5.

Explanation:

6 0
2 years ago
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I need to know the right answer to that question
ad-work [718]
The answer is C 8.87*10^4 m/s (it shouldn't be m/s^2 though as velocity is in m/s)

Since you know the acceleration is 12 m/s^2, the initial velocity is 2.39*10^4 m/s and the time (you have to convert to seconds) is 5400 seconds, then you can use the equation

v = vo + at

When you plug in the values you get

v = 2.39*10^4 + 5400*12 . so v = 8.87*10^4 m/s. C is your answer.
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3 years ago
Which activity is a method of habitat restoration?
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A. cleaning up after environmental disasters

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What must occur for work to be done on an object?
stiv31 [10]
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3 years ago
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A wire of radius 5 x 10⁻⁴ m is needed to prepare a coil of resistance 40 Ω. The resistivity of the material of the wire is 3.14x
SIZIF [17.4K]

Answer:

100 m

Explanation:

From the question,

R = Lρ/A.................... Equation 1

Where R = resistance of the wire, L = length of the wire, ρ = resistivity of the wire, A = cross sectional area of the wire.

But,

A = πr².................... Equation 2

Where r = radius of the wire.

Substitute equation 2 into equation 1

R = Lρ/πr²

Make L the subject of the equation

L = Rπr²/ρ...................... Equation 3

Given: R = 40 Ω, r = 5×10⁻⁴ m, ρ = 3.14×10⁻⁷ Ωm

Constant: π = 3.14

Substitute these values into equation 3

L = [40×3.14×( 5×10⁻⁴)²]/ (3.14×10⁻⁷)

L = 40×3.14×25×10⁻⁸/(3.14×10⁻⁷)

L = 100 m

Hence the length of the wire is 100 m

4 0
2 years ago
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