Answer:
15 mL of the solute
Explanation:
From the question given above, the following data were obtained:
Solution = 50 mL
Solvent = 35 mL
Solute =?
Solution is simply defined as:
Solution = solute + solvent
With the above formula, we can easily obtain the solute in the solution as follow:
Solution = 50 mL
Solvent = 35 mL
Solute =?
Solution = solute + solvent.
50 = solute + 35
Collect like terms
50 – 35 = solute
15 = solute
Solute = 15 mL
Therefore, 15 mL of the solute is required.
Arsenic, I believe. Metalloids fall in between metals and nonmetals (usually on the bold line separating the two on the periodic table). And since the metalloid in question has four electron shells and five valence electrons in the outermost shell, you can see that this element is arsenic
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Explanation:
Answer:
sp3 - 1,2,13,16,18,19
sp2- 3,4,5,6,7,8,9,10,11,12,14,15,17
sp- 0
Explanation:
Hybridization is the idea that atomic orbitals fuse to form newly hybridized orbitals, which in turn, influences molecular geometry and bonding properties (Chemlibretexts).
Carbon atoms that are singly bonded are sp3 hybridized, carbon atoms that are doubly bonded are sp2 hybridized while carbon atoms that are triply bonded are sp hybridized.
Sp3 hybridized atoms have a tetrahedral geometry, sp2 hybridized atoms have a trigonal planar geometry while an sp hybridized atom has a linear geometry.
The hybridization state of each atom in the compound has been shown in the answer section.
Avagadros number states that 1 mol of any substance is made of 6.022 x 10²³ units.
These units could be atoms that make up an element or molecules that make up a compound. CO₂ is a compound therefore its made of CO₂ molecules.
1 mol of CO₂ contains 6.022 x 10²³ molecules of CO₂
Therefore if 6.022 x 10²³ molecules of CO₂ make up 1 mol
then 1.25 x 10¹⁵ molecules of CO₂ make up -

Number of CO₂ moles present - 2.0756 x 10⁻⁹ mol of CO₂