Answer:
MnO- Manganese Oxide
Explanation:
Empirical formula: This is the formula that shows the ratio of elements
present in a
compound.
How to determine Empirical formula
1. First arrange the symbols of the elements present in the compound
alphabetically to determine the real empirical formula. Although, there
are exceptions to this rule, E.g H2So4
2. Divide the percentage composition by the mass number.
3. Then divide through by the smallest number.
4. The resulting answer is the ratio attached to the elements present in
a compound.
Mn O
% composition 72.1 27.9
Divide by mass number 54.94 16
1.31 1.74
Divide by the smallest number 1.31 1.31
1 1.3
The resulting ratio is 1:1
Hence the Empirical formula is MnO, Manganese oxide
The electron configuration for a atom whose element has a atomic number of 8 (Oxygen) is 2,6
I dont understand life, for example, look at my username.
Answer:
13
Explanation:
because the number of protons and electrons in the atom are the same
I am going to assume that the reaction occurs in water since that is the easiest procedure (let me know if I am not supposed to make this assumption).
1) get 2 beakers, the chemicals for the reaction, DI water, and the catalyst.
2) equal volumes and amounts of the water was placed into the 2 beakers.
3) some of the catalyst was added to beaker the second beaker.
3) equal amounts of the chemicals for the reaction was placed into the 2 beakers.
4) the two reactions were compared to see how the un-catalyzed reaction in beaker 1 was effected by the introduction of a catalyst in beaker 2.
I hope this helps. Let me know in the comments if anything was unclear.
