Evaporation, condensation, and precipitation are all parts of the water cycle. So the answer would have to be the water cycle.
The radiosity of this surface is 299.95W/m².
<h3>
Calculation :</h3>
Given, € 0.8
Ta=0°C 273K
For opaque body., T = 0
a+ p = 1
€ = a (Kirchoff's Law)
p = (1-E)
Radiosity = leaving energy from the surface
= px 240 +€σT4
= (1-E) × 240 +0.8 x 5.67 x 10-8 (2734)
= (1-0.8) × 240 +0.8 x 5.67 × 10-8 (2734)
= 299.95W/m²
So, now after doing the calculations we can say that the radiosity of the surface was 299.95W/m².
To know more about Radiosity please click here : brainly.com/question/14937321
#SPJ4
Answer:
higher, left
Explanation:
Given that the reaction consumes 462 kJ of energy. It means that the reaction is a endothermic reaction.
In the energy profile of the endothermic diagrams, The reactants are at a very low level as compared to the products and hence, energy is supplied to overcome this difference.
Hence, The energy levels of products are <u>higher</u> than the energy level of reactant.
Hence, already stated, heat is required by the reaction and thus heat is written to the reactant side which is to the <u>left</u> side of the equation.
The Thiele tube which is look like a triangle, used for the determination of melting and boiling point of the solid and liquid sample respectively. The tube consists of high viscous oil. The mouth of the triangle tube consists the thermometer and the sample through a rubber stopper. The tube is always heated in low flame as the heating mechanism of the oil is through convection current process, in which the molecules of the oil heated passes through out the bulk to make a uniform heat of the liquid. The uniform heat of the liquid is necessary to determine the exact melting point of the solid. Also the low heating rate is compulsory so that the rate of convection current be slow. The high heating rate may cause fast convection in the oil and the hot oil can spill out from the tube and may cause an accident.
Answer:
Explanation:
522 g
Explanation:
Your starting point here will be the balanced chemical equation for this combustion reaction
4
P
(s]
+
5
O
2(g]
→
2
P
2
O
5(s]
Notice that you have a
4
:
5
mole ratio between phosphorus and oxygen. This means that, regardless of how many moles of phosphorus you have, the reaction will always need
5
4
time more moles of oxygen gas.
Use phosphorus' molar mass to determine how many moles you have in that
93.0-g
sample
93.0
g
⋅
1mole P
30.974
g
=
3.0025 moles P
Use the aforementioned mole ratio to determine how many moles of oxygen you would need for many moles of phosphorus to completely take part in the reaction
3.0025
moles P
⋅
5
moles O
2
4
moles P
=
3.753 moles O
2
