There's 6.022×10^23 particles in 1 mole of anything
like there is 1000 grams in 1 kilogram of anything
Answer:
Approximately 
, assuming that this gas is an ideal gas.
Explanation:
Look up the standard room temperature and pressure:
and 
.
The question states that the volume of this gas is 
.
Convert the unit of all three measures to standard units:
.
.
.
Look up the ideal gas constant in the corresponding units: 
.
Let 
denote the number of moles of this gas in that . By the ideal gas law, if this gas is an ideal gas, then the following equation would hold:
.
Rearrange this equation and solve for :
.
In other words, there is approximately 
of this gas in that .
Answer:
mass
Explanation:
It is the amount of matter .
Answer:
904.014 j/kgk
Explanation:
Mass of metal = 45g
Temperature of metal = 85.6°
Mass of water = 150
Temperature of water = 24.6
Final temperature of system = 28.3
Heat lost by metal = Heat gained by water
m1 * c1 * dt = m2 * c2 * dt
Q = quantity of heat
Q = m*c*dt
dt = change in temperature
dt of water = 28.3 - 24.6 = 3.7
dt of metal = 85.6 - 28.3 = 57.3
Specific heat capacity of water, c = 4200
(45 * 10^-3) * c * 57.3 = (150 * 10^-3) * 4200 * 3.7
2.5785c1 = 2331
c1 = 2331 / 2.5785
= 904.01396
= 904.014 j/kgk
