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Ann [662]
2 years ago
15

A sample of gas starts at 1.00 atm, 0.00 degrees Celsius, and 30.0 mL. What is the

Chemistry
1 answer:
lara31 [8.8K]2 years ago
4 0

Answer:

pV= nRT

Explanation:

(p1 × V1)/ T1/ (p2 × V2)/ T2

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Convert 614 Cal to J. Only include the numerical value in your answer. Respond with the correct number of significant figures in
Kruka [31]

Answer:

Explanation:

Given parameters:

Number of given calories = 614 cal

Note that  1cal = 4.18J

Now to convert the given calories to joule, we use the relationship below:

         Since 1Cal gives 4.18Joule of energy

                614Cal will produce 4.18 x 614;

                   2566.52J of energy.

This written as 2.57 x 10³J because it has three significant numbers of 2, 5 and 7.

In writing an operation that involves deducing the significant numbers, we simply express our answer to that shows the lowest number of significant numbers. Our problem has 3 significant numbers each and the answer is given in that regard.

7 0
3 years ago
Whenever a number or a variable is divided<br> by itself, it is always equal to
Jobisdone [24]

Answer:itself

Explanation:

Duh

5 0
3 years ago
The volume of a sample of gas is 0.5 L and the pressure is 0.98 atm. The volume is increased to 1.0 L. Show the set
meriva

Given,

P1 = 0.98 atm

V1 = 0.5 L

V2 = 1.0 L

P2 = ?

Solution,

According to Boyle's Law,

P1V1 = P2V2

0.98 × 0.5 = 1.0 × P2

P2 = 0.98 × 0.5 × 1.0

P2 = 0.49 atm

Answer - The new pressure is 0.49 atm.

5 0
3 years ago
Un mol de Neón ocupa un volumen de 5 lt y una temperatura 300°K, cuál será su volumen si la temperatura disminuye en 50 °K, P y
Anna [14]

Answer:

No hoblo englas

Explanation:

7 0
2 years ago
A gas occupies 100 mL at 150. kPa. Find its volume at 200. kPa. You must show all your work to receive credit. Be sure to identi
PtichkaEL [24]

The Boyle-Mariotte's law or Boyle's law is one of the laws of gases that <u>relates the volume (V) and pressure (P) of a certain amount of gas maintained at constant temperature</u>, as follows:

PV = k

where k is a constant.

We can relate the state of a gas at a specific pressure and volume to another state in which the same gas is at different P and V since the product of both variables is equal to a constant, according to the Boyle's law, which will be the same regardless of the state of the gas. In this way,

P₁V₁ = P₂V₂

Where P₁ and V₁ is the pressure and volume of the gas to a state 1 and P₂ and V₂ is the pressure and volume of the same gas in a state 2.

In this case, in the state 1 the gas occupies a volume V₁ = 100 mL at a pressure of P₁ = 150 kPa. Then, in the state 2 the gas occupies a volume V₂ (that we must calculate through the boyle's law) at a pressure of P₂ = 200 kPa.  Substituting these values in the previous equation and clearing V₂, we have,

P₁V₁ = P₂V₂ → V₂ = \frac{P1V1}{P2}  

→ V₂ = \frac{100 mL x 150 kPa}{200 kPa}

→ V₂ = 75 mL

Then, the volume occupied by the gas at 200 kPa is V₂ = 75 mL

6 0
3 years ago
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