Answer:Yes yes it can
Explanation:Why ? Because Stony Brook University in New York found that CFL bulbs produce incredibly high levels of UVA and UVC emissions, which are harmful to human skin.
Answer:
The carbon cycle
Or
Carbon moves from living things to the atmosphere. Each time you exhale, you are releasing carbon dioxide gas (CO2) into the atmosphere. Animals and plants get rid of carbon dioxide gas through a process called respiration. Carbon moves from fossil fuels to the atmosphere when fuels are burned.
Answer:
sulfite ion SO32
Explanation:
A molecular ion is a covalently bonded set of two or more atoms, or of a metal complex, that can be considered to behave as a single unit and that has a net charge that is not zero.
3.6 moles
required when each quantity of reactant completely reacts.
The ratio of the mole quantities of any two compounds present in a balanced chemical reaction is known as the mole ratio. A reaction's product yield can be predicted using mole ratios, as can the amount of reactant required to produce a specific amount of result.
The balanced chemical equation is :
(l) →
(g) +
(g)
Given is = 2.6 mol 
As we see, 3 moles of
reacts with 4 moles of
.
Therefore,
n(
) = n(
) × 
n(
) = 
n(
) = 3.6 moles.
Therefores, 3.6 moles
required when each quantity of reactant completely reacts.
Learn more about moles here;
brainly.com/question/20486415
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Answer:
The type of mixture whose components are seen through our naked eyes is known as heterogeneous mixture. it is a mixture of small constituent parts of substances.
for eg, mixture of sand and sugar.
<em><u>hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>