Answer:
E) 2.38
Explanation:
The pH of any solution , helps to determine the acidic strength of the solution ,
i.e. ,
- Lower the value of pH , higher is its acidic strength
and ,
- Higher the value of pH , lower is its acidic strength .
pH is given as the negative log of the concentration of H⁺ ions ,
hence ,
pH = - log H⁺
From the question ,
the concentration of the solution is 0.0042 M , and being it a strong acid , dissociates completely to its respective ions ,
Therefore , the concentration of H⁺ = 0.0042 M .
Hence , using the above equation , the value of pH can be calculated as follows -
pH = - log H⁺
pH = - log ( 0.0042 M )
pH = 2.38 .
Shale actually forms in the part of the rock cycle called compaction.
Answer : The percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.
Explanation :
To calculate the percentage composition of element in sample, we use the equation:
![\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20element%7D%3D%5Cfrac%7B%5Ctext%7BMass%20of%20element%7D%7D%7B%5Ctext%7BMass%20of%20sample%7D%7D%5Ctimes%20100)
Given:
Mass of carbon = 1.94 g
Mass of hydrogen = 0.48 g
Mass of sulfur = 2.58 g
First we have to calculate the mass of sample.
Mass of sample = Mass of carbon + Mass of hydrogen + Mass of sulfur
Mass of sample = 1.94 + 0.48 + 2.58 = 5.0 g
Now we have to calculate the percentage composition of a compound.
![\%\text{ composition of carbon}=\frac{1.94g}{5.0g}\times 100=38.8\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20carbon%7D%3D%5Cfrac%7B1.94g%7D%7B5.0g%7D%5Ctimes%20100%3D38.8%5C%25)
![\%\text{ composition of hydrogen}=\frac{0.48g}{5.0g}\times 100=9.6\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20hydrogen%7D%3D%5Cfrac%7B0.48g%7D%7B5.0g%7D%5Ctimes%20100%3D9.6%5C%25)
![\%\text{ composition of sulfur}=\frac{2.58g}{5.0g}\times 100=51.6\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20composition%20of%20sulfur%7D%3D%5Cfrac%7B2.58g%7D%7B5.0g%7D%5Ctimes%20100%3D51.6%5C%25)
Hence, the percentage composition of carbon, hydrogen and sulfur in a compound is, 38.8 %, 9.6 % and 51.6 % respectively.
<span>Well if you're looking for grams, all you need to do is cancel out units.
(ml)(g/ml)=g because the ml cancels out.
Thus, multiply: (85.32ml)(1.03g/ml)=...I'll let you solve this. :)
Good luck! Hope that helped. When in doubt, look at the units.</span>