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Sunny_sXe [5.5K]
2 years ago
5

How can you increase the force required to move an object without changing the mass of the object?

Physics
1 answer:
Effectus [21]2 years ago
8 0

To increase the force required to move an object without change mass is : To increase the acceleration of the object

<h3>Force acting on an object </h3>

Given that Force = Mass * acceleration

An increase in the acceleration of an object in motion will result in a proportional increase in the Force required to move the object becasue force of an object is directly proportional to the acceleration of an object.

Hence we can conclude that To increase the force required to move an object without change mass is To increase the acceleration of the object.

Learn more about Force : brainly.com/question/25239010

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A ball with a mass of 3kg is dropped from the top of a building this is 20m high. what is the velocity of the ball when it is 10
anzhelika [568]

Answer:

Velocity=14[m/s]

Explanation:

We can solve this problem by using the principle of energy conservation, where potential energy becomes kinetic energy.

In the attached image we can see the illustration of the ball falling from the height of 20 meters, at this time the potential energy will have the following value.

Ep=m*g*h\\where:\\m=3[kg]\\h=20[m]\\

Ep=3*9.81*20\\Ep=588.6[J]

When the ball passes through half of the distance (10m) its potential energy will have decreased by half as shown below.

Ep=3*9.81*10\\Ep=294.3[m]

If we know that potential energy is transformed into kinetic energy, we can find the value of speed.

Ek=\frac{1}{2} *m*v^{2} \\therefore\\v=\sqrt{\frac{Ek*2}{m} } \\v=\sqrt{\frac{294.3*2}{3} } \\\\v=14[m/s]

7 0
4 years ago
Which component of the atom has the least mass?
mrs_skeptik [129]

B) Electrons have the least amount of mass

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What is the efficiency of a 0.60 kg basketball that, one dropped from a 2.0 m height (from basket rim) , rebounds to 1.2 m in he
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<h2>Let us find the efficiency : Ans = 0.6</h2>

Explanation:

we know :

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We also know that :

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g = acceleration due to gravity

h = height of body from floor

Thus, output = 0.6 x 10 x 1.2 = 7.2J

Similarly ,input = 0.6 x 10 x 2 = 12J

Thus efficiency = 7.2/12 = 0.6

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