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Sunny_sXe [5.5K]
2 years ago
5

How can you increase the force required to move an object without changing the mass of the object?

Physics
1 answer:
Effectus [21]2 years ago
8 0

To increase the force required to move an object without change mass is : To increase the acceleration of the object

<h3>Force acting on an object </h3>

Given that Force = Mass * acceleration

An increase in the acceleration of an object in motion will result in a proportional increase in the Force required to move the object becasue force of an object is directly proportional to the acceleration of an object.

Hence we can conclude that To increase the force required to move an object without change mass is To increase the acceleration of the object.

Learn more about Force : brainly.com/question/25239010

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A football punter wants to kick the ball so that it is in the air for 4.2 s and lands 55 m from where it was kicked. Assume that
earnstyle [38]

Answer:

57.24^{\circ}

24.21 m/s

Explanation:

x = Displacement in x direction = 55 m

y = Displacement in x direction = 0

y_0 = Height of the ball when the ball is kicked = 1 m

t = Time taken = 4.2 s

a_y=g = Acceleration due to gravity = -9.81\ \text{m/s}^2

u = Initial velocity of ball

Displacement in x direction is given by

x=u_xt+\dfrac{1}{2}a_xt^2\\\Rightarrow 55=4.2u_x+0\\\Rightarrow u_x=\dfrac{55}{4.2}\\\Rightarrow u\cos\theta=13.1\ \text{m/s}\\\Rightarrow u=\dfrac{13.1}{\cos\theta}

Displacement in y direction is given by

y=y_0+u_yt+\dfrac{1}{2}a_yt^2\\\Rightarrow 0=1+4.2u\sin\theta+\dfrac{1}{2}\times (-9.81)\times 4.2^2\\\Rightarrow 0=4.2u\sin\theta-85.5242\\\Rightarrow u\sin\theta=20.36\ \text{m/s}\\\Rightarrow u=\dfrac{20.36}{\sin\theta}

\dfrac{13.1}{\cos\theta}=\dfrac{20.36}{\sin\theta}\\\Rightarrow \dfrac{20.36}{13.1}=\dfrac{\sin\theta}{\cos\theta}\\\Rightarrow \theta=\tan^{-1}\dfrac{20.36}{13.1}\\\Rightarrow \theta=57.24^{\circ}

The ball should be kicked at an angle of 57.24^{\circ}

u=\dfrac{13.1}{\cos\theta}=\dfrac{13.1}{\cos57.24^{\circ}}\\\Rightarrow u=24.21\ \text{m/s}

The initial speed of the ball is 24.21 m/s.

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<span>ZnS(s) + 2O2(g) mc011-1.jpg ZnSO4(s) CaO(s) + H2O(l) </span>
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Answer:

1 astronomical unit, or AU, is the average distance from the Earth to the Sun; that's about 150 million km. So, Neptune's average distance from the Sun is 30.1 AU. Its perihelion is 29.8 AU, and it's aphelion is 30.4 AU.

Short Answer: it is 29

Explanation:

sorry if its wrong

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