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Elena L [17]
3 years ago
15

What is NOT one of the three primary resources that families have to reach financial goals?

Physics
1 answer:
Elodia [21]3 years ago
8 0
What is NOT one of the three primary resources that families have to reach financial goals? It is c) education
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If an equation is dimensionally correct is thar equation a right equation<br>​
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If an equation is dimensionally correct, it does not mean that the equation must be true. On the other hand, when the equation is dimensionally correct, the equation cannot be true. Dimensional analysis is a technique used to check whether a relationship is correct

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A flap of tissue that prevents blood from flowing back is a(n)________ .
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A valve is a flap of tissue that prevents blood from flowing back
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Read 2 more answers
A child of mass m is standing at the edge of a carousel. Both the carousel and the child are initially stationary. The carousel
suter [353]

Answer:

the angular velocity of the carousel after the child has started running =

\frac{2F}{mR} \delta t

Explanation:

Given that

the mass of the child = m

The radius of the disc = R

moment of inertia I = \frac{1}{2} mR^2

change in time = \delta \ t

By using the torque around the inertia ; we have:

T = I×∝

where

R×F = I × ∝

R×F = \frac{1}{2} mR^2∝

F = \frac{1}{2} mR∝

∝ = \frac{2F}{mR}           ( expression for angular  angular acceleration)

The first equation of motion of rotating wheel can be expressed as :

\omega = \omega_0  + \alpha  \delta t

where ;

∝ = \frac{2F}{mR}    

Then;

\omega = 0+ \frac{2F}{mR} \delta t

\omega =  \frac{2F}{mR} \delta t

 

∴ the angular velocity of the carousel after the child has started running =

\frac{2F}{mR} \delta t

7 0
3 years ago
Influenced by the gravitational pull of a distant star, the velocity of an asteroid changes from from +19.3 km/s to −18.8 km/s o
muminat

As per above given data

initial velocity = 19.3 km/s

final velocity = - 18.8 km/s

now in order to find the change in velocity

\Delta v = v_f - v_i

\Delta v = -18.8 - 19.3

\Delta v = -38.1 km/s

\Delta v = -3.81 * 10^4 m/s

Part b)

Now we need to find acceleration

acceleration is given by formula

a = \frac{\Delta v}{\Delta t}

given that

\Delta v =- 3.81 * 10^4 m/s

\Delta t = 2.07 years = 6.53 * 10^7 s

now the acceleration is given as

a = \frac{-3.81 * 10^4}{6.53 * 10^7}

a = - 5.84 * 10^{-4}m/s^2

so above is the acceleration

4 0
3 years ago
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