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lutik1710 [3]
3 years ago
11

you slide across home plate during baseball game. If you have a mass of 82 kg, and the coefficient of kinetic friction between y

ou and the ground is 0.45, what is the force of friction acting on you?
Physics
2 answers:
Tju [1.3M]3 years ago
8 0

m = mass of the person = 82 kg

g = acceleration due to gravity acting on the person = 9.8 m/s²

F = normal force by the surface on the person

f = kinetic frictional force acting on the person by the surface

μ = Coefficient of kinetic friction = 0.45

The normal force by the surface in upward direction balances the weight of the person in down direction , hence

F = mg                                          eq-1

kinetic frictional force on the person acting is given as

f = μ F

using eq-1

f = μ mg

inserting the values

f = (0.45) (82) (9.8)

f = 361.6 N

dexar [7]3 years ago
5 0

Answer:

362 rounded, a p e x users

Explanation:

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a) In order to draw a sketch of the situation, I must include the data I know, the data I would like to know and a drawing of the car including the direction of the movement and its acceleration, just like in the attached picture.

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x=x_{0}+V_{x0}t+\frac{1}{2}a_{x}t^{2}

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x=0+0(12s)+\frac{1}{2}(2.40\frac{m}{s^{2}} )(12s)^{2}

after cancelling the pertinent units, I get that  my answer will be given in meters. So I get:

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I need to find the final velocity, so I need to use an equation that will use some or all of the known data and the unknown. In order to solve this problem, I can use the following equation:

a=\frac{V_{f}-V_{0} }{t}

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