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lutik1710 [3]
3 years ago
11

you slide across home plate during baseball game. If you have a mass of 82 kg, and the coefficient of kinetic friction between y

ou and the ground is 0.45, what is the force of friction acting on you?
Physics
2 answers:
Tju [1.3M]3 years ago
8 0

m = mass of the person = 82 kg

g = acceleration due to gravity acting on the person = 9.8 m/s²

F = normal force by the surface on the person

f = kinetic frictional force acting on the person by the surface

μ = Coefficient of kinetic friction = 0.45

The normal force by the surface in upward direction balances the weight of the person in down direction , hence

F = mg                                          eq-1

kinetic frictional force on the person acting is given as

f = μ F

using eq-1

f = μ mg

inserting the values

f = (0.45) (82) (9.8)

f = 361.6 N

dexar [7]3 years ago
5 0

Answer:

362 rounded, a p e x users

Explanation:

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t = 2; Vₓ = 3.00 + 0.100 (2)² = 3.40

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9) Range: Vₓ ∈ [ 3.00, 5.50]

10) All that information permits you to put several points in a coordinate sysment and sketch the same graph as the shown in the figure attached.

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