Their velocity afterwards is 2.88 m/s east
Explanation:
We can solve this problem by using the law of conservation of momentum. In fact, for an isolated system (= no external force), the total momentum must be conserved before and after the collision. So we can write:
where: in this case:
is the mass of the first player
is the initial velocity of the first player (choosing east as positive direction)
is the mass of the second player
is the initial velocity of the second player
is their combined velocity afterwards
Solving for v, we find:
And the sign is positive, so the direction is east.
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Answer:
v = 3.84 m/s
Explanation:
In order for the riders to stay pinned against the inside of the drum the frictional force on them must be equal to the centripetal force:
where,
v = minimum speed = ?
g = acceleration due to gravity = 9.81 m/s²
r = radius = 10 m
μ = coefficient of friction = 0.15
Therefore,
<u>v = 3.84 m/s</u>
Explanation :
It is given that, a heavy box is in the back of a truck and the truck is accelerating to the right.
The description is shown in<em> figure 1</em>. Here, the forces that act on both box and the truck are the normal force, the frictional force and their weight mg.
The free body diagram is shown in <em>figure 2</em>. This shows the total forces ( F = ma )acting on the truck. As a result, the truck will move in a forward direction.
Hence, this is the required explanation.
Answer:
10044 N
Explanation:
The acceleration of the cab is calculated using the equation of motion:
<em>v</em> is the final velocity = 0 m/s in this question, since it is brought to rest
<em>u</em> is the initial velocity = 10 m/s
<em>a</em> is the acceleration
<em>s</em> is the distance = 35 m
Since it accelerates downwards, its resultant acceleration is
<em>g</em> is the acceleration of gravity.
The tension in the cable is