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MaRussiya [10]
4 years ago
13

The equation of a circle whose center is (3,7) and whose radius is 6 is

Mathematics
1 answer:
Aleks [24]4 years ago
4 0
The equation of any given circle is:
{(x - h)}^{2}  +  {(y - k)}^{2}  =  {r}^{2}
where (h, k) is the center and r is the radius.

In the problem, we are given the center, and the radius. When we plug them in:
{(x - 3)}^{2}  +  {(y - 7)}^{2}  = 36
we got the formula of the circle.
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The fuse are building a new home one of the bedroom closet has an area of 48 square feet and a perimeter of 32 ft what are the l
olya-2409 [2.1K]

Answer: The length is 12 feet and the width is 4 feet.

Step-by-step explanation:

Let L represent the length of the bedroom closet.

Let W represent the width of the bedroom closet..

The formula for determining the perimeter of a rectangle is expressed as

Perimeter = 2(L + W)

The perimeter of the bedroom closet is 32 ft. This means that

2(L + W) = 32

Dividing through by 2, it becomes

L + W = 32/2

L + W = 16

The area of the bedroom closet is 48 ft². This means that

LW = 48 - - - - - - - -- - - - - - 1

Substituting L = 16 - W into equation 1, it becomes

W(16 - W) = 48

16W - W² = 48

W² - 16W + 48 = 0

W² - 12W - 4W + 48 = 0

W(W - 12) - 4(W - 12) = 0

W - 12 = 0 or W - 4 = 0

W = 12 or W = 4

L = 16 - 4 = 12

3 0
4 years ago
4 ? 10<br> 9 22 <br><br> Do these two ratios form a proportion
Sav [38]
Yes because they as fraction would be equal parts I think
8 0
3 years ago
Solve by completing the square<br><br>x squared +14x - 51=0
Nesterboy [21]
x^2 +14x - 51=0\\ \\\Delta = b^{2}-4ac =14^{2}-4*1*(-51)=196+204=400 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{-14- \sqrt{400}}{2}=\frac{-14-20}{2}= \frac{-34}{2}=-17\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{-14+ \sqrt{400}}{2}=\frac{-14+20}{2}= \frac{6}{2}=3


3 0
4 years ago
Here is my answer to ur question
bagirrra123 [75]
Uh Answer to what-
Bro you good?
6 0
3 years ago
Find the value of w.<br><br><br><br><br><br> w= ?
Stolb23 [73]
W=80
365 subtract by all the other angles
7 0
3 years ago
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