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aleksley [76]
2 years ago
9

A 2.03 kg book is placed on a flat desk. Suppose the coefficient of static friction between the book and the desk is 0.602 and t

he coefficient of kinetic friction is 0.327 . How much force is needed to begin moving the book
Physics
1 answer:
diamong [38]2 years ago
5 0

Answer:

11.98 N

Explanation:

Normal force =   mg =  2.03 * 9.81

coeff of static friction must be overcome for the book to begin moving

       .602 = F / (2.03 * 9.81)   = 11.98  N

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A spacecraft in the shape of a long cylinder has a length of 100 m, and its mass with occupants is 1 480 kg. It has strayed too
maks197457 [2]

Answer:

2352645198509.9604 m/s²

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of black hole = 90\times 1.989\times 10^{30}\ kg

R_{f} = 10000+100 m

R_{sb} = Distance between the nose and the center of the black hole = 10000 m

The difference in the gravitational field in this system is given by

\Delta F=\dfrac{GMm}{R_{f}^2}-\dfrac{GMm}{R_{sb}^2}\\\Rightarrow \Delta g=GM\left(\frac{1}{R_f^2}-\frac{1}{R_{sb}^2}\right)\\\Rightarrow g=6.67\times 10^{-11}\times 90\times 1.989\times 10^{30}\left(\frac{1}{(10000+100)^2}-\frac{1}{10000^2}\right)\\\Rightarrow \Delta g=-2352645198509.9604\ m/s^2

The acceleration is 2352645198509.9604 m/s²

4 0
3 years ago
4. The chart shows melting and boiling points of
kondor19780726 [428]

Answer:

The correct option is A

Explanation:

Firstly, it should be noted that the freezing point of a substance can be assumed to be melting point of that substance because a substance will normally change from liquid to solid (freezes) at the same point it changes from solid to liquid (melts). For example, water freezes at 0°C and also starts melting at 0°C.

Thus, the substance with the lowest melting point among the substances mentioned in the question is alcohol (ethanol) with the melting point of -114°C. Hence, <u>ethanol also has the lowest freezing point thereby freezing at the lowest temperature.</u>

6 0
3 years ago
A wooden block of mass m = 9 kg starts from rest on an inclined plane sloped at an angle θ from the horizontal. The block is ori
vredina [299]

Answer:

f = 0.283

Explanation:

With the given values x=5m and t=2s, the acceleration a of the block must be:

(1) a=\frac{2x}{t^2}

The sum of all forces in the inclined plane must be:

(2) F=ma=sin(\theta) F_{gravity}-F_{friction}=sin(\theta) mg - f cos(\theta) mg

Solving equation2 for the acceleration a:

(3) a=sin(\theta) g - f cos(\theta) g

Using equations 1 and 3 to solve for f:

\frac{2x}{t^2}=sin(\theta) g - f cos(\theta) g\\f=tan(\theta)-\frac{2x}{t^2cos(\theta)g}

4 0
3 years ago
An implanted pacemaker supplies the heart with 72 pulses per minute, each pulse providing 6.0 V for 0.65 ms. The resistance of t
9966 [12]

Answer: a) 0.11 Amp b) 0.000429 Joules c) 0.000514 watt

Explanation:

a)current

I=V/r I=6.0/550 =1.1*10^-2 A

b) energy

E= 1.1*10^-2 x (6.0) x 0.00065s(<-- remember to convert ms to seconds) = 0.000429J

C) Average power

P = (0.000429 x 72) / 60

P = 0.000514 W

6 0
3 years ago
What radiant energy is sensed by human skin as warmth
almond37 [142]
Infrared radiation <span>is sensed by human skin as warmth.</span>
4 0
3 years ago
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